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mote1985 [20]
3 years ago
9

I don't get how to do this, can someone help?​

Mathematics
1 answer:
Marianna [84]3 years ago
4 0
Google helps to so try that
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If a and b are odd integers,then a-b is an even integer identify the conclusion
garri49 [273]
Any two odd integers will always add up to an even number. Examples include 1+1=2, 15+19=34, etc. 
6 0
3 years ago
You , malakhi , yanis , nyla , Aaliyah go to a new tapas restaurant in jamaica , queens each of you order 6 small dishes that ea
BlackZzzverrR [31]

each dish costs two dollars.

3 0
3 years ago
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
In the diagram shown of circle A, segments UV and UT are congruent. If
grandymaker [24]

Answer:

 35°

Step-by-step explanation:

We assume that points S, T, U, V all lie on the circle.

Inscribed angle TUV intercepts long arc VST and short arc VUT. The long arc has measure 220°, so the measure of the short arc is 360° -220° = 140°.

Since chords UV and UT are the same length, point U bisects arc VUT. That means the measure of arc VU is 140°/2 = 70°.

Inscribed angle VSU intercepts arc VU, so has half the measure of the arc:

 ∠VSU = 70°/2

 ∠VSU = 35°

Read more on Brainly.com - brainly.com/question/15559971#readmore

8 0
3 years ago
I need help with IXL​
Damm [24]

Answer:

ok whats up

Step-by-step explanation:

3 0
3 years ago
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