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mote1985 [20]
3 years ago
9

I don't get how to do this, can someone help?​

Mathematics
1 answer:
Marianna [84]3 years ago
4 0
Google helps to so try that
You might be interested in
Analyze tables use the table that shows the percents of blood types of 145 donors during a recent blood drive
Alenkinab [10]

Answer:

a. 16

b. 80

c. Blood type AB

Step-by-step explanation:

Given:

O = 45%

A = 40%

B = 11%

AB = 4%

Total number of donors = 145

a. No. of donors that had type B blood = \frac{11}{100}*145 = \frac{1,595}{100} = 15.95

Type B blood donors ≈ 16

b. No. of blood donors without blood type O = \frac{40 + 11 + 4}{100}*145 = \frac{55}{100}*145 = \frac{7,975}{100} = 79.75

Those without blood type O ≈ 80

c. Find the number of people that had type AB:

Type AB = \frac{4}{100}*145 = 5.8 ≈ 6. This is less than 10 donors.

Therefore, blood type AB had less than 10 donors.

6 0
3 years ago
The sides of △FGH are FG = 6 x+ 7, GH = 8x - 5, and FH = 10x - 11. If the perimeter of △FGH is 87, list the angles in order from
irga5000 [103]

Answer:

From largest to smallest: FG, FH, GH

Step-by-step explanation:

Given

FG = 6x + 7

GH = 8x - 5

FH = 10x - 11

Perimeter = 87

Required

Order the sides in descending order

First, we need to solve for x.

Perimeter of FGH is calculated as thus:

Perimeter = FG + GH + FH

Substitute values for FG, GH, FH and Perimeter

87 = 6x + 7 + 8x - 5 + 10x - 11

Collect Like Terms

87 - 7 + 5 + 11= 6x + 8x + 10x

96= 24x

Reorder

24x = 96

Divide through by 24

x = 96/24

x = 4

Substitute 4 for x in FG, GH and FH

FG = 6x + 7

FG = 6 * 4 + 7

FG = 24 + 7

FG =31

GH = 8x - 5

GH = 8 * 4 - 5

GH = 32 - 5

GH = 27

FH = 10x - 11

FH = 10*4 - 11

FH = 40 - 11

FH = 29

In order of arrangement in descending order, we have:

FG =31    FH = 29     GH = 27

4 0
3 years ago
NEED HELP ASAP!!
Kaylis [27]

Answer:

20²+21² = x²

841= x²

x= 29

nearest tenth = 30

4 0
3 years ago
Read 2 more answers
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
Suppose that an experiment is repeated four times. A certain event has probability 1/10 in a single repetition of the
frez [133]

Answer:

2/5

Step-by-step explanation:

1/10 times 4

4/10 equals to 2/5

5 0
3 years ago
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