When the chef turned the new freezer on, the temperature on the internal thermometer was 2 °C.

Mathematics

1 answer:

motikmotik2 years ago

7 0

Answer: -13 °C.

Step-by-step explanation:

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<h2> The six trigonometric functions, $\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\tan \dfrac{\pi}{4} =1$ , $\cot \dfrac{\pi}{4} =1$ , $\sec \dfrac{\pi}{4} =\sqrt{2}$ and $\csc \dfrac{\pi}{4} =\sqrt{2}$ .</h2>

Step-by-step explanation:

We have,

$\dfrac{\pi}{4}$

To write the six trigonometric functions = ?

$\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$

$\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$

$\tan \dfrac{\pi}{4} =1$

$\cot \dfrac{\pi}{4} =1$

$\sec \dfrac{\pi}{4} =\sqrt{2}$

$\csc \dfrac{\pi}{4} =\sqrt{2}$

∴ The six trigonometric functions, $\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\tan \dfrac{\pi}{4} =1$ , $\cot \dfrac{\pi}{4} =1$ , $\sec \dfrac{\pi}{4} =\sqrt{2}$ and $\csc \dfrac{\pi}{4} =\sqrt{2}$ .