Answer:
a) ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
b) therefore Basis of W is
={
}
Step-by-step explanation:
Given the data in the question;
W = { A| Air Skew symmetric matrix}
= {A | A = -A^T }
A ; O⁻ = -O⁻^T O⁻ : Zero mstrix
O⁻ ∈ W
now let A, B ∈ W
A = -A^T B = -B^T
(A+B)^T = A^T + B^T
= -A - B
- ( A + B )
⇒ A + B = -( A + B)^T
∴ A + B ∈ W.
∝ ∈ | R
(∝.A)^T = ∝A^T
= ∝( -A)
= -( ∝A)
(∝A) = -( ∝A)^T
∴ ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
A ∈ W
A = -AT
A = ![\left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Do%26a%26b%5C%5C-a%26o%26c%5C%5C-b%26-c%260%5Cend%7Barray%7D%5Cright%5D)
=
![+c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]](https://tex.z-dn.net/?f=%2Bc%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%260%5C%5C0%260%261%5C%5C0%26-1%260%5Cend%7Barray%7D%5Cright%5D)
therefore Basis of W is
={
}
Answer:
C. 8
Step-by-step explanation:
![\because \: {s}^{3} = 64 \\ s = \sqrt[3]{64} \\ s = 4 \\ side \: of \: cube = 4 \: units \\ when \: side \: is \: halved \\ new \: side \: length = \frac{4}{2} = 2 \\ \: new \: volume = {2}^{3} = 8 \: cubic \: units](https://tex.z-dn.net/?f=%20%5Cbecause%20%5C%3A%20%20%7Bs%7D%5E%7B3%7D%20%20%3D%2064%20%5C%5C%20s%20%3D%20%20%5Csqrt%5B3%5D%7B64%7D%20%20%5C%5C%20s%20%3D%204%20%5C%5C%20side%20%5C%3A%20of%20%5C%3A%20cube%20%3D%204%20%5C%3A%20units%20%5C%5C%20when%20%5C%3A%20side%20%5C%3A%20is%20%5C%3A%20halved%20%5C%5C%20new%20%5C%3A%20side%20%5C%3A%20length%20%3D%20%20%5Cfrac%7B4%7D%7B2%7D%20%20%3D%202%20%5C%5C%20%20%5C%3A%20new%20%5C%3A%20volume%20%3D%20%20%7B2%7D%5E%7B3%7D%20%20%3D%208%20%5C%3A%20cubic%20%5C%3A%20units)
<span>1. Measure the distance the solvent front traveled from the baseline (m1). 2. Measure the distance the reactant b spot traveled (the center of the spot) (m2). 3. To determine the rf, divide (m2/m1). 4. Significant figures- use 2 so the answer should be written to the hundredths place as the spot will not travel farther than the solvent front.</span>
Diagram not attached, please add the question.
2* 10^4 would be bigger than 8* 10^3.
10^4 = 10000*2=20000
10^3 = 1000*8=8000