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2 years ago

A traveler first drives 21.0 km east, then 29.1 km southeast, and finally 10.3 km south. Find the traveler's total displacement.

Physics

1 answer:

Vinvika [58]2 years ago

7 0

The traveler's total displacement is 53.2 km.

The shortest distance between a particle's starting position and destination is referred to as its displacement vector. Displacement has a distinct physical magnitude than distance. Let's use the motion of a particle making a complete circle as an example. The displacement in this motion is zero, yet the distance traveled is equal to the circle's circumference. The individual displacement vectors are as follows: d1

=22^ikm→d2

= (29.7cos45i29.7sin45) kmd3=104jkm

The traveler's complete disadvantage is,

→d=→d1+→d2+→d3→d

=22^ikM+29.7

cos45^−29.7sin45o) km−10.4^j km→

d=(43^i−31.4^j) km

The magnitude of the total displacement is,

d=√432+31.4/2Km d≈53.2km

The direction is,

θ=tan−1(−31.4/43)

θ=−36.1or 36.1 south of east.

Learn more about displacement here-

brainly.com/question/11934397

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A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration 20.3

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Answer:

a) -2.34 m

b) -1.3 m/s

c) 0.056 m

d) 0.320 m/s

Explanation:

part a

Given:

s(0) = 0.27 m

v(0) = 0.14 m/s

a = -0.320 m/s^2

t = 4.50s

Using kinematic equation of motion for constant acceleration:

s (t) = s(0) + v(0)*t + 0.5*a*t^2

s ( 4.5 s ) = 0.27 + 0.14*4.5 + 0.5*-0.32*4.5^2

s(4.5) = -2.34 m

part b

Using kinematic equation of motion for constant acceleration:

v(t) = v(0) + a*t

v(4.5s) = (0.14) + (-0.32)(4.5) = -1.3 m/s

part c

Use equation for simple harmonic motion:

s(t) = A*cos(w*t)

v(t) = -A*w*sin (w*t)

a(t) = -A*(w)^2 * cos (w*t)

0.27 m = A*cos(w*t) .... Eq 1

0.14 m/s = - A*w*sin (w*t) .....Eq2

-0.320 = -A*(w)^2 * cos (w*t) .... Eq3

Solve the three equations above for A, w, and t

Divide 1 and 3:

w^2 = 0.32 / 0.27

w = 1.0887 rad / s

Divide 2 and 1:

w*tan(wt) = 0.14 / 0.27

tan(1.0887*t) = 0.476289

t = 0.4083 s

A = 0.27 / cos (1.0887*0.4083) = 0.3 m

Hence, the SHM is s(t) = 0.3*cos(1.0887*t)

s(4.5) = 0.3*cos(1.0887*4.5) = 0.056 m

part d

v(t) = - 0.32661 * sin (1.0887*t)

v(4.5) = - 0.32661 * sin (1.0887*4.5) = 0.320 m/s

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3 years ago

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Sedaia [141]

Answer:

The force will be $F_{c}=2.47 N$

Explanation:

Let's use the centripetal force equation.

$F_{c}=m\omega ^{2}R$

Where:

m is the mass of the bunch of bananas

ω is the angular speed

R is the radius

Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.

$\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}$

FInally, the force will be:

$F_{c}=2.0*1.57^{2}*0.5$

$F_{c}=2.47 N$

I hope it helps you!

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