Question

Curious George is whirling a 2.0 kg bunch of bananas on a smooth floor in a circular path having a radius of 0.50 m. What force must he apply to keep the motion constant so that the bananas complete one revolution every 4.0 seconds

Answer 1

Answer:

The force will be $F_{c}=2.47 N$

Explanation:

Let's use the centripetal force equation.

$F_{c}=m\omega ^{2}R$

Where:

m is the mass of the bunch of bananas

ω is the angular speed

R is the radius

Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.

$\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}$

FInally, the force will be:

$F_{c}=2.0*1.57^{2}*0.5$

$F_{c}=2.0*1.57^{2}*0.5$

$F_{c}=2.47 N$

I hope it helps you!