Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answers:
<h2>1. 35 </h2><h2>2. 12</h2>
Step-by-step explanation:
Those brackets indicate absolute value. Absolute value is the distance of a number from 0 on the number line. In other words, negatives don't matter. There is also no such thing as a negative absolute value.
-2 -1 0 1 2
Both -2 and 2 are the same distance from 0, just in the opposite direction. Both numbers have the same absolute value, which is 2.
Hope This helps. If it did, then....
<em>PLEASE MARK BRAINLIEST</em>
Answer:
The equation for "continual" growth (or decay) is A = Pert, where "A", is the ending amount, "P" is the beginning amount (principal, in the case of money), "r" is the growth or decay rate (expressed as a decimal), and "t" is the time (in whatever unit was used on the growth/decay rate).
Step-by-step explanation:
<h2>
Don't sweat here is a video link too </h2>
Compounding Continuously Pert Formula
https://youtu.be/dFsBfi9W7sQ
Well, remember
(ab)(cd)=abcd=(ac)(bd)
so
(8t^5)(8t^5)=(8)(t^5)(8)(t^5)=(8*8)(t^5*t^5)=64t^10
Answer: 9/13
Step-by-step explanation:
the numerator goes on the top
the denominator goes on the bottom
