All categories

3 years ago

Plz solve PLZ PLZ PLZ PZL

Mathematics

1 answer:

Firlakuza [10]3 years ago

4 0

Answer:

Step-by-step explanation:

A: No, because you can't switch signs of a number to another sign unless you change the number itself.

B: Yes. It has the same numbers and signs and the result is negative (there are an odd amount of negative signs)

You might be interested in

A circle has a radius of 8cm. What is the AREA? Use this formula - A = pi X radius squared.

Studentka2010 [4]

Step-by-step explanation:

The formula for the area of a circle: $A=\pi r^{2}$

Given:

Radius = 8 cm

Substitute 8 for r (radius):

$A=\pi 8^{2}$

Solve:

$A=\pi (64)$

$A=64\pi$ $or$ $201.062 cm^{2}$ $rounded.$

3 0

3 years ago

Ill give brainllest what is 18+26+37+36+8+28?

Rashid [163]

Answer:

153

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Solve for x x-23=17 a -40 b 40 c -6 d 6

natali 33 [55]

Answer: It is B - 40

Step-by-step explanation:

40-23 = 17

7 0

3 years ago

Read 2 more answers

Write the equation in standard form. Identity the center and radius. x² + y2 + 8x-4y-7=0

lorasvet [3.4K]

Answer:

equation;

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

Center (-4,2)

Radius is

$3 \sqrt{3}$

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

$(x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$

Where (h,k) is center

r is the radius

So first we group like Terms together

${x}^{2} + 8x + {y}^{2} - 4y - 7 = 0$

Add 7 to both sides

${x}^{2} + 8x + {y}^{2} - 4y = 7$

$( {x}^{2} + 8x) +( {y}^{2} - 4y) = 7$

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

$(\frac{8}{2} ) {}^{2} = 16$

and

$( - \frac{4}{2} ) {}^{2} = 4$

so we have

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 7 + 16 + 4$

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 27$

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

$\sqrt{27} = 3 \sqrt{3}$

So the radius is 3 times sqr root of 3.

8 0

2 years ago

Look at the box-and-whisker plot.

Marizza181 [45]

i would say B

when it says "the measure", it's refering to where the second quartile is beginning

3 0

4 years ago