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Annette [7]
2 years ago
12

You determine that a sample of a compound contains 1. 4 mol c and 2. 1 mol h. What is the empirical formula for this compound?.

Chemistry
1 answer:
vlada-n [284]2 years ago
8 0

The empirical formula of the compound is C4H1.

An empirical formula represents the whole number ratio of various atoms present in a compound.

If the mass percent of various elements present in a compound is known, its empirical formula can be determined

We are given that a compound contains 4 mole C and 1 mole H.

Hence, the ratio of C: H is 4:1, which is already in the form of the simplest whole number.

Therefore, the empirical formula of the given compound is C4H1 and its molecular mass is 12 x 4 + 1 = 49.

To know more about "Empirical Formula", refer to the following link:

brainly.com/question/14044066?referrer=searchResults\

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If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
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The mass of calcium sulfate that will precipitate is 6.14 grams

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<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

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<u>Step 2:</u> Calculate moles of Ca^2+

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Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

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<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]  

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Qsp = (0.050)(0.050 )=0.0025 >> Ksp

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<u> Step 6:</u> Calculate molar solubility

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x = √(2.40 * 10^-5)

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<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

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