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2 years ago

You determine that a sample of a compound contains 1. 4 mol c and 2. 1 mol h. What is the empirical formula for this compound?.

Chemistry

1 answer:

vlada-n [284]2 years ago

8 0

The empirical formula of the compound is C4H1.

An empirical formula represents the whole number ratio of various atoms present in a compound.

If the mass percent of various elements present in a compound is known, its empirical formula can be determined

We are given that a compound contains 4 mole C and 1 mole H.

Hence, the ratio of C: H is 4:1, which is already in the form of the simplest whole number.

Therefore, the empirical formula of the given compound is C4H1 and its molecular mass is 12 x 4 + 1 = 49.

To know more about "Empirical Formula", refer to the following link:

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Suppose you have 250g of gold(I) Chloride. How many grams of Gold do you have?

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29.26 gram

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No of molecules = no of mole × Avogadro's number

No of molecules = mass in gram/ molar mass × Avogadros number

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2 years ago

A sample of a gas in a rigid container has an initial pressure of 1.049 kPa and an initial temperature of 7.39 K. The temperatur

Doss [256]

Answer:- 4.36 kPa

Solution:- At constant volume, the pressure of the gas is directly proportional to the kelvin temperature.

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Where the subscripts 1 and 2 are representing initial and final quantities.

From given data:

$P_1$ = 1.049 kPa

$P_2$ = ?

$T_1$ = 7.39 K

$T_2$ = 30.70 K

For final pressure, the equation could also be rearranged as:

$P_2=\frac{P_1T_2}{T_1}$

Let's plug in the values in it:

$P_2=\frac{1.049kPa(30.70K)}{7.39K}$

$P_2$ = 4.36 kPa

So, the new pressure of the gas is 4.36 kPa.

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3 years ago