Lithium i think!!
hope this helps
The specific heat, c is 0.75 J/g°C
<u>Explanation:</u>
Heat or Energy, Q = 1500J
Mass, m = 50g
T1 = 0°C
T2 = 40°C
Specific Heat, c = ?
We know,
Q = mcΔT
Q = mc(T2-T1)
1500 = 50 X c X (40-0)
1500 = 50 X c X 40
c = 1500/ 2000
c = 0.75 J/g°C
Therefore, the specific heat, c is 0.75 J/g°C
Answer: what are the answers to the questions
Explanation:
The empirical and molecular formula : C₂₁H₂₂N₂O₂
<h3>Further explanation</h3>
Given
The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen,
8.38 % Nitrogen, and 9.57 % Oxygen
Required
The empirical and molecular formula
Solution
C : 75.42 : 12 = 6.285
H : 6.63 : 1 = 6.63
N : 8.38 : 14 = 0.599
O : 9.57 : 16 = 0.598
Divide by 0.598
C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2
The empirical formula : C₂₁H₂₂N₂O₂
(C₂₁H₂₂N₂O₂)n = 334
(334)n=334
n = 1