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ahrayia [7]
3 years ago
5

how does increasing concentration/ temperature/ surface area affect the yield of products in a chemical reaction (not reversible

)
Chemistry
1 answer:
egoroff_w [7]3 years ago
6 0
Answer:
             <span>Increasing concentration, temperature and surface area will increase the yield of products.

Explanation:
                   Concentration:
                                           
Increase in concentration of reactants will increase the number of reactants per unit volume. Therefore, the probability of collisions will increase hence, it will result in the increase in yield.

                   Temperature:
                                        Increase in temperature increases the kinetic energy of reactants. Therefore, the increase in velocity of reactants results in the collisions with high energy. It makes it feasible for reactants to attain the optimum energy (activation energy) to convert into products with good yield.

                  Surface Area:
                                       The reactants in grinded / powder form reacts fast as compared to solid form. In fact, grinding results in increase of the surface area of reactants. Greater surface area increases the probability of reactants to colloid. Hence, increases the yield.</span>
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HELP PLEASE ASAP
Anna [14]

Answer:

d

Explanation:

Aluminium and Indian are in the same group/family

Sodium and Sulfer are in the same period

Elements of the same family have similar properties

Since sulfur and sodium aren't in the same family they dont share properties

3 0
2 years ago
What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim
Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means P_{2} =\frac{P_{1} }{10}

Given the volume of the system increased by 5 times which means V_{2} =5\times V_{1}

Given final temperature T_{2}=150K

Let the initial temperature be T_{1}

We know that PV=nRT

As n and R are constant \frac{PV}{T}=constant

\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}

T_{1} =2\times T_{2}

T1=300K

8 0
3 years ago
Item 3
svetoff [14.1K]

Answer:

Semiconductors are poor conductors at low temperatures, but their resistance decreases with increasing temperature.

Explanation:

A semiconductor can be defined as a crystalline solid substance that has its conductivity lying between that of a metal and an insulator, due to the effects of temperature or an addition of an impurity. Semiconductors are classified into two main categories;

1. Extrinsic semiconductor.

2. Intrinsic semiconductor.

The statement which best describes the electrical conductivity of metals and semiconductors is that semiconductors are poor conductors at low temperatures, but their resistance decreases with increasing temperature.

This ultimately implies that, semiconductors are typically an insulator (poor conductor) at low temperatures and a good conductor at high temperatures.

Additionally, conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.

6 0
3 years ago
In an acid-base titration experiment, 50 mL of a 0.05 M solution of acetic acid (Ka= 1.75 x 10-5 ) was titrated with a 0.05M sol
Viktor [21]

Answer:

(3) 5.36

Explanation:

Since this is a titration of a weak acid before reaching equivalence point, we will have effectively a buffer solution. Then we can use the Henderson-Hasselbalch equation to answer this question.

The reaction is:

HAc + NaOH ⇒ NaAc + H₂O

V NaOH = 40 mL x 1 L/1000 mL = 0.040 L

mol NaOH reacted with HAc = 0.040 L x 0.05 mol/L = 0.002 mol

mol HAC originally present = 0.050 L x 0.05 mol/L = 0.0025 mol

mol HAc left after reaction = 0.0025 - 0.002 = 0.0005

Now that we have calculated the quantities of the weak acid and its conjugate base in the buffer, we just plug the values into the equation

pH = pKa + log ((Ac⁻)/(HAc))

(Notice we do not have to calculate the molarities of  Ac⁻ and HAc because the volumes cancel in the quotient)

pH = -log (1.75 x 10⁻⁵) + log (0.002/0.0005) = 5.36

THe answer is 5.36

5 0
3 years ago
Read 2 more answers
Bromine can be classified as a
sergiy2304 [10]

Answer:

Halogen / salt-former

Explanation:

Bromine is classified as an element in the 'Halogens' section which can be located in group 7 of the Periodic Table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts".

8 0
3 years ago
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