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ahrayia [7]
3 years ago
5

how does increasing concentration/ temperature/ surface area affect the yield of products in a chemical reaction (not reversible

)
Chemistry
1 answer:
egoroff_w [7]3 years ago
6 0
Answer:
             <span>Increasing concentration, temperature and surface area will increase the yield of products.

Explanation:
                   Concentration:
                                           
Increase in concentration of reactants will increase the number of reactants per unit volume. Therefore, the probability of collisions will increase hence, it will result in the increase in yield.

                   Temperature:
                                        Increase in temperature increases the kinetic energy of reactants. Therefore, the increase in velocity of reactants results in the collisions with high energy. It makes it feasible for reactants to attain the optimum energy (activation energy) to convert into products with good yield.

                  Surface Area:
                                       The reactants in grinded / powder form reacts fast as compared to solid form. In fact, grinding results in increase of the surface area of reactants. Greater surface area increases the probability of reactants to colloid. Hence, increases the yield.</span>
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What is the mode of action of most antifungal drugs?
Goshia [24]

Inhibition of protein synthesis is the mode of action done by most antifungal drugs.

<h3>What is the mode of action of antifungal drugs?</h3>

Antifungals drugs inhibit the synthesis of ergosterol the main fungal sterol, polyenes which interact with fungal membrane sterols and 5-fluorocytosine inhibits macromolecular synthesis.

So we can conclude that inhibition of protein synthesis is the mode of action done by most antifungal drugs.

Learn more about drug here: brainly.com/question/26254731

3 0
2 years ago
What is the freezing point of a solution in which 2.50 grams of sodium chloride are added to 230.0 ml of water
labwork [276]

The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is :  - 0.69°C

<h3>Determine the freezing point of the solution </h3>

First step : Calculate the molality of NaCl

molality =  ( 2.5 grams / 58.44 g/mol ) / ( 230 * 10⁻³ kg/ml )

              = 0.186  mol/kg

Next step : Calculate freezing point depression temperature

T = 2 * 0.186 * kf

where : kf = 1.86°c.kg/mole

Hence; T = 2 * 0.186 * 1.86 = 0.69°C

Freezing point of the solution

Freezing temperature of solvent - freezing point depression temperature

                                               0°C  -  0.69°C = - 0.69°C

Hence the Freezing temperature of the solution is  - 0.69°C

Learn more about The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is :  - 0.69°C

8 0
2 years ago
How much is the oxygen valency?
Marina CMI [18]
The oxygen valency is 2
4 0
3 years ago
Which of the following is composed of weathered rocks and decomposed organic material from dead plants and animals?
Amanda [17]
Soil is made from dead plants, animals, and rocks.
8 0
4 years ago
Read 2 more answers
The Haber process for the production of ammonia is the main industrial process of producing ammonia today. Prior to developing t
Schach [20]

Answer:

Equilibrium constant for the reaction at 25⁰C = 1.81 x 10⁻⁶

Explanation:

                            Reaction for the Haber's process

                              N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g)

Free energy change of reaction

                    ΔGr° = ∑products free energy - ∑reactants free energy

                             = 2 x (- 16.4) - 0

                             = - 32.8 KJ / mole

Equilibrium constant for this reaction at 25⁰C

                           ΔGr° = - 2.303 RT log K

                      ⇒  log K = \frac{-32.8}{2.303 X8.314X10^{-3}X 298 }

                      ⇒        K = Anti log( -5.74) = 1.81 x 10⁻⁶

6 0
4 years ago
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