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ahrayia [7]
3 years ago
5

how does increasing concentration/ temperature/ surface area affect the yield of products in a chemical reaction (not reversible

)
Chemistry
1 answer:
egoroff_w [7]3 years ago
6 0
Answer:
             <span>Increasing concentration, temperature and surface area will increase the yield of products.

Explanation:
                   Concentration:
                                           
Increase in concentration of reactants will increase the number of reactants per unit volume. Therefore, the probability of collisions will increase hence, it will result in the increase in yield.

                   Temperature:
                                        Increase in temperature increases the kinetic energy of reactants. Therefore, the increase in velocity of reactants results in the collisions with high energy. It makes it feasible for reactants to attain the optimum energy (activation energy) to convert into products with good yield.

                  Surface Area:
                                       The reactants in grinded / powder form reacts fast as compared to solid form. In fact, grinding results in increase of the surface area of reactants. Greater surface area increases the probability of reactants to colloid. Hence, increases the yield.</span>
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5 0
2 years ago
Calculate the specific heat for as air if 1500.0 joules are required to raise the temperature of 50.0g from 0.0c to 40.0c
Law Incorporation [45]

The specific heat, c is 0.75 J/g°C

<u>Explanation:</u>

Heat or Energy, Q = 1500J

Mass, m = 50g

T1 =  0°C

T2 = 40°C

Specific Heat, c = ?

We know,

Q = mcΔT

Q = mc(T2-T1)

1500 = 50 X c X (40-0)

1500 = 50 X c X 40

c = 1500/ 2000

c = 0.75 J/g°C

Therefore, the specific heat, c is 0.75 J/g°C

7 0
3 years ago
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Maurinko [17]

Answer: what are the answers to the questions

Explanation:

5 0
3 years ago
If there are 1,000 mg in 1<br> gram. Then how many mg are<br> in 2.5 grams?
mihalych1998 [28]

Answer:

1 gram =1000mg

Explanation:

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2500mg

7 0
3 years ago
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guapka [62]

The empirical and  molecular formula : C₂₁H₂₂N₂O₂

<h3>Further explanation</h3>

Given

The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen, 8.38 % Nitrogen, and 9.57 % Oxygen

Required

The empirical and  molecular formula

Solution

C : 75.42 : 12 = 6.285

H : 6.63 : 1 = 6.63

N : 8.38 : 14 = 0.599

O : 9.57 : 16 = 0.598

Divide by 0.598

C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2

The empirical formula : C₂₁H₂₂N₂O₂

(C₂₁H₂₂N₂O₂)n = 334

(334)n=334

n = 1

8 0
3 years ago
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