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MatroZZZ [7]
2 years ago
6

What is the average atomic mass of an element that has 3 isotopes with the data below?

Chemistry
1 answer:
Bezzdna [24]2 years ago
3 0

Answer:

How do you calculate the average atomic mass of three isotopes?

To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together. Whenever we do mass calculations involving elements or compounds (combinations of elements), we always use average atomic masses

Explanation:

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Does it require more energy to "vaporize" water at the boiling point or to melt water at the melting point? Explain.
sveticcg [70]

Answer:

yes I think so because more heat evaporates water

7 0
2 years ago
PLEASE HELPP ASAP!!!!!What is the equation for density A. D=M/V B. D=V/M C. D= M/V2 D. D=1/2 MV2
mestny [16]

The correct answer is option A.

D = M/V

The density of a substance is the ratio of its mass to its volume.

Density = mass / volume

or D = M/V

The unit of density is gram per milliliter or g/ml, when mass is expressed in gram or g and the volume is expressed in milliliter ml.

If we know the mass and volume of a substance we can calculate its density using the formula for density.


8 0
3 years ago
What is the only nonmetal with four valence electrons?.
mamaluj [8]

Answer:

Carbon

Explanation:

I just finished this and that's what I got from my periodic table.

7 0
2 years ago
Only someone who truly knows and understands this, please tell me if the electron configurations are right :
Setler79 [48]
Yes is 4s^23d^7=cobalt
4 0
3 years ago
Calculate the concentration in mol L^-1 of ammonium ions in a solution prepared by mixing 360 mL of 0.250 mol L^-1 ammonium sulf
Mnenie [13.5K]

In order to determine the concentration of ammonium ions in the solution prepared by mixing solutions of ammonium sulfate, (NH4)2SO4, and ammonium nitrate, first calculate the amount of ammonium ions for each solution.<span>

<span>For ammonium sulfate sol'n: 0.360 L x 0.250 mol(NH4)2SO4/ L x 2 mol NH4+ /1 mol(NH4)2SO4 = 0.18 mol NH4+
<span>For ammonium nitrate sol'n: 0.675 x 1.2 mol NH4NO3/L x 1 mol NH4+ /1 molNH4NO3 = 0.81 mol NH4+

Thus, the amount of NH4+ ions is (0.18 + 0.81) mol or 0.99 mol NH4+. To get the concentration, multiply this to the volume of solution which is assumed to be additive, such that:</span></span></span>

M NH4+ in sol’n = 0.99 mol NH4+/1.035 L = 0.9565 mol NH4+/ L sol’n

8 0
3 years ago
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