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3 years ago

For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula

of the simplest compound that the ions are most likely to form. Write the formula of the metal first and follow by the non metal

Chemistry

1 answer:

Dafna11 [192]3 years ago

4 0

$\\ \sf\longmapsto FeP$

$\\ \sf\longmapsto Fe_2S_3$

$\\ \sf\longmapsto FeCl_2$

$\\ \sf\longmapsto MgCl_2$

$\\ \sf\longmapsto MgO$

$\\ \sf\longmapsto Mg_3N_2$

$\\ \sf\longmapsto Na_3P$

$\\ \sf\longmapsto Na_2S$

$\\ \sf\longmapsto CoO$

$\\ \sf\longmapsto Co_2S_3$

$\\ \sf\longmapsto AlCl_3$

$\\ \sf\longmapsto CsBr$

$\\ \sf\longmapsto Ti_2O_4$

$\\ \sf\longmapsto Ag_2S$

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The concentration of C29H60 in summer rainwater is 34 ppb. Find the molarity of this compound in nanomoles per liter (nM).

Naya [18.7K]

Answer: The concentration of C29H60 in nM per liter is 83,33 nM/liter

Explanation: Let's start from the ppb definition: ppb means parts per billion. In terms of concentracion measuring this means micrograms of solute per liter of solution.

The algebraic expression would be:

ppb [=] micrograms of compound/liter of solution

We can assume that the solvent is water. The solute is dissolved in water and both create the C29H60 solution.

For the exercise we have 34 ppb of C29H60, that means 34 micrograms of C29H60 in one liter of solution. So, since now, we have to convert the units from the initial data to the required answer.

The respective procedure is in a attached file.

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3 years ago

Question 4

elixir [45]

Answer:

True

Explanation:

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3 years ago

Identify the term that matches each definition.

Nikolay [14]

Answer:

a. Volatile.

b. Air foil.

c. Sash.

d. Work surface.

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are;

I. Solid.

II. Liquid.

III. Gas.

Matching the terms with their respective definition, we have;

a. Volatile: A characteristic that describes substances that evaporate readily, producing large amounts of vapors.

b. Air foil: the front vent of a fume hood, which helps maintain proper air circulation.

c. Sash: the glass panel in front of the fume hood that shields the user from fumes and other hazards.

d. Work surface: the horizontal, flat area of a fume hood upon which experiments are carried out.

7 0

3 years ago

a) Calculatethe molality, m, of an aqueous solution of 1.22 M sucrose, C12H22O11. The density of the solution is 1.12 g/mL.b) Wh

Contact [7]

Answer:

a) 1,74 molal

b) 37,2 %

c) 0,03

Explanation:

We are going to define sucrose as solute, water as solvent and the mix of both, the solution.

Let´s start with the data:

$Molarity = M = \frac{1,22 mol solute}{lts solution}$

We can assume as a calculus base, 1 liter of solution. So, in 1 liter of solution we have 1,22 moles of solute:

$1 lts solution * \frac{1,22 moles solute}{lts solution}=1,22 moles solute$

Knowing that the molality (m) is defined as mol of solute/kgs solvent, we have to calculate the mass of solvent on the solution. Remember our calculus base (1 lts of solution). In 1 lts of solution we have 1120 grams of solution.

$1 lts solution * \frac{1,12 grs solution}{mL solution}*\frac{1000 mL solution}{1 lts solution} = 1120 grs of solution$

With the molecular weight of solute (Sum of: for carbon = 12*12=144; for hydrogen = 1*22=22 and for oxygen = 16*11=176. Final result = 342 grs per mol), we can obtain the mass of solute:

$1,22 mol solute*\frac{342 grs solute}{1 mol solute} = 417,24 grs solute$

Now, the mass of solvent is: mass solvent = mass of solution - mass of solute. So, we have: 1120 - 417,24 = 702,76 grs of solvent = 0,70276 Kgs of solvent

$molality = m = \frac{1,22 mol solute}{0,70276 kgs solvent}= 1,74 molal$

For b) question we have that the mass percent of solute is hte ratio between the mass of solute and the mass of solution. So,

$%(w/w) = \frac{417,24 grs solute}{1120 grs solution} = 37,2%$

For c) question we have that the mole fraction of solute is the ratio between moles of solute and moles of solution. Let's calculate the moles of solution as follows: Moles solution = moles solute + moles solvent. First we have that the moles of solvent are (remember that the molecular weight of water for this calculus is 18 grs per mol):

$702,76 grs solvent*\frac{1 mol solvent}{18 grs solvent} = 39,04 moles solvent$

So, we have the moles of solution: 1,22 moles of solute + 39,04 moles of solvent = 40,26 moles of solution

Finally, we have:

$Mol frac solute = \frac{1,22 mol solute}{40,26 mol solution}= 0,03$

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3 years ago

Something that dissolves in liquid solven solute solution

Feliz [49]

Answer: solute

Explanation:

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