We know that
[volume of the similar prism]=10*5*5----> 250 in³
volume original prism=16 cm³
1 in³---------> 16.3871 cm³
X----------> 16
x=16/16.3871------> x=0.9764 in³
[volume of the similar prism]=[scale factor]³*[volume original prism]
[scale factor]³=[volume of the similar prism]/[volume original prism]
[scale factor]³=[250]/[0.9764]------> 256.05
scale factor=∛256.05-------> 6.35
<span>the dimensions of the original prism are
1 in-----> 2.54 cm
</span>length 10 in/6.35-------> 1.57 in*2.54 cm/in-----> 4 cm
<span>width 5 in/6.35---------> 0.79 in*2.54 cm/in-----> 2 cm
</span><span>height 5 in/6.35--------> 0.79 in*2.54 cm/in----> 2 cm</span>
Answer:
It's 8
Step-by-step explanation:
![16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8](https://tex.z-dn.net/?f=%2016%20%5E%7B%20%5Cfrac%7B3%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B16%20%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B2%20%5E%7B4%20%5Ctimes%203%7D%20%7D%20%3D%202%5E%7B%20%5Cfrac%7B12%7D%7B4%7D%20%7D%20%20%20%3D%202%5E%7B3%7D%20%20%3D%208)
Whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0
Svetllana [295]
In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in
adult females. To calculate the arm span for the heights given, we add
5cm to their height. The following are the results:
Height Arm Span Length (in cm)
4’10 152.32
4’11 154.86
5’0 157.4
5’4 167.56
5’5 170.10
5’7 175.18
5’8 177.72
5’9 180.26
5’10 182.80
5’11 185.34
6’0 187.88
To add, the total measurement of the length from the furthermost
part of an individual's arms to the other end
when raised equidistant to the ground at shoulder height at a 90º angle
is called the arm span or wingspan.
