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2 years ago

If a radioactive decay produced 2. 05 × 1011 j of energy, how much mass was lost in the reaction?

Physics

1 answer:

Morgarella [4.7K]2 years ago

6 0

The mass lost in the reaction is 0.227 × $10^{-5}$ Kg

The energy that is released during a nuclear reaction can be related to the mass lost using the Einstein equation.

E = m $c^{2}$ by Einstein demonstrates that matter and energy are only two different manifestations of the same thing. It also demonstrates how much energy (E) can fit into a relatively small mass (m) of matter. Nuclear processes convert matter into energy, yet the combined amount of mass and energy remains constant.

Given that;

E = Δ $mc^{2}$

Δm = $\frac{ E}{c^{2} }$

Δm = 2. 05 × 10^11 J/( 3 × 10^8)^2

Δm = 0.227 × $10^{-5}$ Kg

Learn more about Einstein's equation:

brainly.com/question/10809666

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What is the magnitude of a point charge that produces a potential of -200V at a distance of 1.00 mm?

schepotkina [342]

Answer:

$q=-2.22*10^{-11}C$

Explanation:

The potential produces by a point charge is given by:

$V=\frac{kq}{r}$

Here, k is the Coulomb constant, q is the signed magnitude of the point charge and r is the distance between the charge and the point at which the electric potential is measured. Solving for q:

$q=\frac{rV}{k}\\q=\frac{1*10^{-3}m(-200V)}{8.99*10^9\frac{V\cdot m}{C}}\\q=-2.22*10^{-11}C$

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3 years ago

A 40-W lightbulb is 1.7 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra

Sonja [21]

Answer:

Intensity, $I=1.101\ W/m^2$

Explanation:

Power of the light bulb, P = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

$I=\dfrac{P}{A}$

$I=\dfrac{P}{4\pi r^2}$

$I=\dfrac{40\ W}{4\pi (1.7\ m)^2}$

$I=1.101\ W/m^2$

So, the intensity of light is $1.101\ W/m^2$ .

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4 years ago

The latent heat of vaporization for water at room temperature is 2430 J/g.

alukav5142 [94]

Answer:

1) $kinectic energy=7.26*10^-^2^0J$

2) $V= 2.0m/s$

3) $T=3.5*10^3K$

4) The Molecules do not burn because of the presences of hydrogen bond in place

Explanation:

From the question we are told that

latent heat of vaporization for water at room temperature is 2430 J/g.

1)Generally in determining the molar mass of water evaporated we have that

-One mole (6.02 x 10. 23 molecules)

-Molar mass of water is 18.02 g/mol

Mathematically the mass of water is give as

$M=\frac{18.02}{6.02*10^-^2^6}$

$M=3*10^-^2^3g$

Therefore

$kinectic energy=2430J/g*3*10^-^2^3g$

$kinectic energy=7.26*10^-^2^0J$

b)Generally the evaporation speed V is given as $V= \sqrt{\frac{K.E*2}{m} }$

Mathematically derived from the equation

$\frac{1}{2} mv^2 =K.E$

To Give

$V= \sqrt{\frac{K.E*2}{m} }$

$V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }$

$V= 2.0m/s$

c)Generally the equation for velocity $Vrms=\sqrt{\frac{3RT}{M} }$

Therefore

Effective temperature T is given by

$T=\frac{\sqrt{v}*m}{R}$

where

$T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}$

$T=3.5*10^3K$

4) The Molecules do not burn because of the presences of hydrogen bond in place

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3 years ago

Lumbar nerves transmit signals that allow us to?

labwork [276]

Lumbar nerves transmit signals that allow us to walk. They are a pivotal part of the human body, and without them we would be immobile. Hope this helps.

7 0

4 years ago

Read 2 more answers

A 13500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the

Mekhanik [1.2K]

Answer

given,

mass of the jet airplane = 13500 kg

Force on the plane = 35700 N due north

force from wind = 15300 N in direction 80.0° south of west.

Force = $35700 \vec{j} N$