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Bumek [7]
3 years ago
13

If you jumped out of a plane, you would begin speeding up as you fall downward. Eventually, due to wind resistance, your velocit

y would become constant with time. While your velocity is constant, the magnitude of the force of wind resistance is
Physics
1 answer:
MrRa [10]3 years ago
5 0

Answer:

Mg or your weight.

Explanation:

When your velocity is constant, the net force acting on you is 0. That means the upwards force of air resistance must fully balance the downwards force of gravity on you, which is Mg.

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What is the gravitational force between two identical 5000 kg asteroids whose centers of mass are separated by 100 m?
Alenkinab [10]

Answer: 1.67 x 10^-7N

Explanation:

5 0
3 years ago
Which is not an example of a scalar?
Crank

Answer:

b) 2ft/s

Explanation:

A scalar has only magintude, not direction

6.2m, 3kg, and -100 o C are all scalars because they only have magnitude.

2ft/s is not a scalar because it has a direction.

3 0
2 years ago
an eskimo pushes a loaded sled with a mass of 300kg over the frictionless surface of hard-packed snow.he exerts a constant 170n
Shalnov [3]

Answer:

0.567 m/s²

Explanation:

Newton's second law:

∑F = ma

170 N = (300 kg) a

a = 0.567 m/s²

Round as needed.

3 0
3 years ago
Read 2 more answers
Two small charged spheres are located on the y-axis. One is at y = 1.00 m, the other is at y = −1.00 m, and they both have a cha
yuradex [85]

Answer:

(a) 23.946 kV

(b) -0.077 J

Explanation:

(a) The electric potential is given by the following formula:

V=k\frac{q_1}{r_1}+k\frac{q_2}{r_2}   (1)

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

q1 = q2 = 1.60*10^{-6}C

r1 and r2 are the distance from the charges to the point in which electric potential is evaluated.

Firs, you calculate the distance r1 and r2 by taking into account the position of the charges

r_1=\sqrt{(1.00)^2+(0.670)^2}m=1.20m\\\\r_2=\sqrt{(-1.00)^2+(0.670)^2}m=1.20m

Next, you replace the values of the parameters to calculate V:

V=(8.98*10^9Nm^2/C^2)\frac{1.6*10^{-6}C}{1.20m}+(8.98*10^9Nm^2/C^2)\frac{1.6*10^{-6}C}{1.20m}\\\\V=23946.66\ V=23.946\ kV

(b) The potential electric energy is given by:

U_T=U_{1,2}+U_{1,3}+U_{2,3}\\\\U_T=k\frac{q_1q_2}{r_{1,2}}+k\frac{q_1q_3}{r_{1,3}}+k\frac{q_2q_3}{r_{2,3}}\\\\r_{1,2}=2.00m\\\\r_{1,3}=1.20m\\\\r_{2,3}=1.20m\\\\U_T=(8.98*10^9)[\frac{(1.6*10^{-6})^2}{2.00m}+\frac{(1.6*10^{-6})(-3.70*10^{-6})}{1.20}+\frac{(1.6*10^{-6})(-3.70*10^{-6})}{1.20}]J\\\\U_T=-0.077J

5 0
3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,
Serhud [2]
By using the equation speed = distance/time we can solve for distance. The speed is 4 m/s and the time is 12 seconds. We need to rearrange the equation to Speed * Time = distance. 4(12) = 48; 48 = distance. The cliff is 48 meters high.
3 0
3 years ago
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