This is an easy answer sure in the back of your mind u knew it was b good luck :).
Answer:
#include <iostream>
using namespace std;
int main()
{
char str[100][20];
int n;
cout<<"Strings you want to enter"<<endl;
cin>>n;
cout<<"enter n strings"<<endl;
for(int i=0;i<n;i++)
cin>>str[i];
for(int i=0;i<n;i++)
{
if((int)str[i][0]==98) //ascii value b is 98
cout<<str[i]<<endl;
}
return 0;
}
Explanation:
The above written code is for printing the strings which starts with the letter b.
To check if the string starts with a letter b we are checking the ascii value 98 which corresponds to b and then printing those strings.
Answer:
That's because the value has reached the size limit of the int data type. ... you should use long rather than int , because long can store much larger numbers than int . If ... In other words, a float or double variable can't accurately represent 0.1 . ... If you're using Java to measure the size of your house, you'd need an electron ...
Explanation:
Association of C and C++ Users (ACCU) is a worldwide association of
people who are interested in C, C++, and related programming languages.
