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soldi70 [24.7K]
3 years ago
9

The empirical formula of a compound is determined to be CH2O, and its molecular mass is found to be 90.087 g/mol. Determine the

molecular formula of the compound, showing your solution.
Chemistry
2 answers:
Grace [21]3 years ago
7 0
<span>In order to do that, we first have to calculate the "molar mass" of empirical unit

12+2*1+16 = 30

so 90/30 = 3

so you have 3*(CH2O) --> C3H6O3

hope this helps</span>
enot [183]3 years ago
5 0
The empirical formula of a compound is determined to be CH2O, and its molecular mass is found to be 90.087 g/mol. Determine the molecular formula of the compound, showing your solution.

Answer: This is actually quite simple, first we have to calculate the molar mass of empirical unit. Therefore we have 12+2*1+16 = 30. Then we solve 90/30 = 3. Finally we end up with 3*(CH2O) --> C3H6O3.

I hope it helps, Regards.
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The given symbol P^{3-} has a -3 charge that means it has gained 3 electrons so, the number of electrons in the P^{3-} is: 15+3 = 18. The number of protons will remain same that is the number of protons = 15.

So, the ion P^{3-} has 15 protons and 18 electrons that gives 15-18=-3 charge on the P^{3-} ion.

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Which two solutions would be the BEST choice for their experiment?
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Solutions 1 and 3 because they are strong acids and a strong base. <u>Option A.</u>

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One of the simplest tests to determine whether a solution is an acid or base is the litmus paper test. To do this, dip a special strip of paper so-called litmus paper into the solution and observe the color of the paper. Litmus paper turns red in acidic solutions and blue in basic solutions. Sodium hydroxide is the strongest base because it completely dissociates to form sodium and hydroxide ions. These hydroxide ions are further treated with hydrogen ions by an acid to completely ionize the hydrogen ions.

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Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrofluoric acid and potassium hydroxide are
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H⁺(aq) + OH⁻(aq) ⇒ H₂O(l)

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HF(aq) + KOH(aq) ⇒ KF(aq) + H₂O(l)

The complete ionic equation includes all the ions and molecular species.

H⁺(aq) + F⁻(aq) + K⁺(aq) + OH⁻(aq) ⇒ K⁺(aq) + F⁻(aq) + H₂O(l)

The net ionic equation includes only the ions that participate in the reaction and the molecular species.

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