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horsena [70]
4 years ago
5

What is the primary greenhouse gas?

Chemistry
1 answer:
elena55 [62]4 years ago
8 0
I think co 2 maybe
I cant remember
You might be interested in
What type of reaction takes place when potassium iodide reacts with chlorine gas?
Roman55 [17]

Answer:

The correct answer is - d. single replacement or displacement.

Explanation:

The displacement or replacement reaction is the reaction in which the less reactive molecule or element is replaced by the more reactive element or molecule in the reaction. If there is only one replacement occurs its termed as a replacement or single replacement reaction.

In this case, if chlorine gas passes through the water solution of KI (potassium iodide), solid iodine and KCl are produced by the displacement or replacement reaction. Here iodine is less reactive so replaced by the more reactive chlorine.

                                 2KI(aq)+Cl2 (g)→2KCl(aq)+I2 (s)

4 0
3 years ago
What is the anode of a galvanic cell made with zinc and aluminum?
amm1812

Answer:

Aluminum Metal

Explanation:

A P E X states that it is Aluminum Metal 100% right

6 0
3 years ago
PLEASE HELP
choli [55]

Answer:

Explanation:

D .Celsius temperature

3 0
3 years ago
1. The Tyndall Effect is most useful for distinguishing between: *
Yuki888 [10]

Answer:

a colloid and a solution

Explanation:

When solute particles completely dissolve in a solvent, a true solution is formed. The solute particles in this case are so little that they can not be seen with naked eyes. A true solution does not scatter rays of light.

In a false solution, the solute particles are larger than the solute particles in true solutions but are not large enough to be seen with naked eyes. False solutions scatter rays of light. False solutions are also called colloids.

The major difference between a solution and a colloid is that colloids scatter light rays (Tyndall effect) while a true solution does not scatter light rays.

5 0
3 years ago
For each given [H3O+] or [OH-], find the corresponding [OH-] or [H3O+] at 25°C.
-BARSIC- [3]

Answer:

a) [H3O+] = 1.00 E-10 M ⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M ⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M ⇒ [OH-] = 1.0 E-9 M

Explanation:

  • 14 = pH + pOH
  • pH = - Log [H3O+]

a) [H3O+] = 1.00 E-10 M

⇒ pH = - Log(1.00 E-10) = 10

⇒ pOH = 14 - 10 = 4

⇒ 4 = - Log[OH-]

⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M

⇒ pH = 4

⇒ pOH = 10

⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M

⇒ pH = 5

⇒ pOH = 9

⇒ [OH-] = 1.0 E-9 M

8 0
3 years ago
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