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horsena [70]
3 years ago
5

What is the primary greenhouse gas?

Chemistry
1 answer:
elena55 [62]3 years ago
8 0
I think co 2 maybe
I cant remember
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Explain the concept of "like dissolves like"
SCORPION-xisa [38]

Answer:

Like dissolves like" is an expression used by chemists to remember how some solvents work. It refers to "polar" and "nonpolar" solvents and solutes. Basic example: Water is polar. Oil is non polar. ... Like dissolves like, that means polar dissolves polar, so water dissolves salt.

Explanation:

7 0
3 years ago
Which scientists is credited with developing the firdt scientific atomic theory
ratelena [41]

<em>Answer: </em>John Dalton

Explanation: Democritus was a Greek philosopher (470-380 B.C.) who is the father of modern atomic thought. He proposed that matter could NOT be divided into smaller pieces forever. John Dalton created the very first atomic theory.

5 0
3 years ago
⚠️PLEASE HELP NO LINKS⚠️<br><br>The question is down below
Shtirlitz [24]

Answer:

D

Explanation:

pretty sure

4 0
3 years ago
How many molecules are present in 265 moles of CCl
Solnce55 [7]

Answer:

Option C. 1.60x10^26 molecules

Explanation:

Avogadro's hypothesis proved that that 1 mole of any substance contains 6.02x10^23 molecules.

From the above, we understood that 1 mole of CCl4 contains 6.02x10^23 molecules.

If 1 mole of CCl4 contains 6.02x10^23 molecules,

then, 265 moles of CCl4 will contain = 265 x 6.02x10^23 = 1.60x10^26 molecules

From the calculation made above, 265 moles of CCl4 contains 1.60x10^26 molecules.

5 0
3 years ago
Which volume of oxygen, at room temperature and pressure, is needed for complete combustion
adell [148]
The molecular formula of methylpropan-1-ol is C4H10O, so the complete combustion equation is: C4H10O + 6O2 --> 4CO2 + 5H2O.  This mean to completely combust 1.0mol of methylpropan-1-ol, 6 mol of O2 is required. Molar mass of O2 is 32 g/mol, so 32g/mol x 6mol = 192 g of O2 is required.  At room temperature and pressure, the density of O2 is 1.3315 g/L (this can be obtained by density of gas = P/RT).  So the volume of O2 = mass/density = 192g/1.3315(g/L) = 144 L = 144 dm3. The answer is B.
5 0
3 years ago
Read 2 more answers
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