By the charge density, the surface area of the cylinder charge is 0.20 nC.
We need to know about charge density to solve this problem. The charge density can be determined as
λ = Q / A
where λ is charge density, Q is charge and A is surface area.
The parameter given is the charge density and the solid cylinder shape which are :
λ = 15 nC/m²
r = 2.5 cm = 0.025 m
L = 6.0 cm = 0.06 m
Find the surface area of cylinder
A = 2πrL + 2πr²
A = 2π. 0.025. 0.06 + 2 . π . 0.025²
A = 0.0134 m²
Find the charges
Q = λ x A
Q = 15 x 0.0134
Q = 0.20 nC
Hence, the surface area of the cylinder charge is 0.20 nC.
Find more on charge density at: brainly.com/question/14568868
#SPJ4