Question

A window washer drops a brush from a scaffold on a tall office building. What is the speed of the falling brush after 3.28 s? (Neglect drag forces.) The acceleration due to gravity is 9.8 m/s^2. Answer in units of m/s.

Answer 1

Answer:

The speed of washer will be 32.144 m/s

Explanation:

Given that

time t= 3.28 s

Acceleration due to gravity

 $g=9.8\ \frac{m}{s^2}$

Here acceleration  is constant so we cam apply the motion equation

we know that

v= u + at

At initial condition  u =0 m/s

v= u + at

v= 0 + 9.8 x 3.28

v= 32.144 m/s

So the speed of washer will be 32.144 m/s

Answer 2

Answer:

The speed of brush is 32.144 m/s.

Explanation:

Given that,

Time = 3.28 s

We need to calculate the speed

Using equation of motion

$v = u+gt$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

Put the value into the formula

$v = 0+9.8\times3.28$

$v =32.144\ m/s$

Hence, The speed of brush is 32.144 m/s.