Answer:
The velocity must change but not speed.
Explanation:
- Velocity is defined as the displacement by time. Whereas speed is expressed as the distance between two successive positions of the body to the time interval it took to travel.
<em>Velocity, V = D / t m/s</em>
<em> Speed, s = d /t m/s </em>
- Velocity is a vector quantity that has a magnitude and direction.
- The speed is a scalar quantity having only the magnitude.
- At any instant of time, the magnitude of the velocity is always equal to the magnitude of the speed. The magnitude of velocity, |<em>v </em>| = magnitude of speed, |<em>v </em>|. The magnitude is always positive
- The acceleration of a body is defined as the rate of change of velocity to time.
<em> a = (v - u) / t m/s²</em>
- If a body is accelerating, It varies its velocity with respect to time.
- In case of uniform circular motion, the speed remains constant, but the velocity changes continuously.
So, in the case of circular motion if an object accelerates, velocity must change but speed remains constant.
Light slows down when it passes from the air to the cornea because the cornea supply’s two thirds of the power of the eye. The speed of light changes significantly when traveling from air into the cornea.
Answer:
115, 80, 15m
Explanation
t1 = 14s
t2 = 18s
change in time = 4s (18-14)
r(final) = r(initial) + (average velocity) x (change in time)
multiply the average velocity with the change in time
= (4, 0, -3) x 4 = 16, 0, -12
now we'll add this value to the initial position of the car
(99, 80, 27)m + (16, 0, -12)m = (115, 80, 15)m
Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
