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tensa zangetsu [6.8K]

3 years ago

7

Find the indicated angle measure m L ABC = 115 A B

1 answer:

Misha Larkins [42]3 years ago

5 0

Answer:

Step-by-step explanation:

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Multiply the following numbers. Reduce the answer to lowest terms.<br><br> 3 1/5 x 2 1/7

Veseljchak [2.6K]

Answer:

48/7

Step-by-step explanation:

= 3 <u> </u><u>1</u><u> </u> × 2 <u> </u><u>1</u><u> </u>

5. 7

= <u> </u><u>1</u><u>6</u><u> </u> × <u> </u><u>1</u><u>5</u><u> </u>

5. 7

= <u> </u><u>2</u><u>4</u><u>0</u><u> </u> , if we divide both numbers by 5 we get;

35

= <u> </u><u>4</u><u>8</u><u> </u>

7

4 0

2 years ago

The number line below represents the lengths, in inches, of fish that can be kept when caught on a certain lake. What does the s

o-na [289]

Answer:

the answer is the third one.

Step-by-step explanation:

the number line is closed circle and at least means greater than or equal to so the answer is "C".

8 0

3 years ago

What type of number is -2i?

Iteru [2.4K]

Answer:

It is an imaginary number.

Step-by-step explanation:

In this example, the real number is -2 is being multiplied by the imaginary unit, i, which i can be also expressed as (√-1).

7 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

-4v-12=-12-4v I need so much help!!!!

tankabanditka [31]

Answer:

0 = 0

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers