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3 years ago

6

There are 28 student desks in Ms.Johnson's.Each desk measures 26.17 inches long.If you were to line up all the desk end-to-end,h

ow long would all the desk be?

1 answer:

iragen [17]3 years ago

4 0

Answer:

To find the answer to this question we need to multiply the number of desks by the length of each desk.

26.17 × 28 = 732.76

So the final answer is 732.76 inches

Step-by-step explanation:

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Solve the equation. Show all of your work. 1/59X + 60) = 2/3x- 2

vivado [14]

Step-by-step explanation:

1/5x+60=2/3x-2

subtract 1/5x from 2/3x

when you do that you should get 0.46x repeating

then you add two to 60

you should get 62

62=0.46x

divide x

you get 134.7

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3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

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4 years ago

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Your answer is ab -c

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Then subtract C

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