Let a,b,,c and x elements in the group G. In each of the following solve for x in terms of a,b,c, and c.

Mathematics

1 answer:

Marrrta [24]3 years ago

3 0

We have

$x^2a=bxc^{-1}\implies x^2ac=bxc^{-1}c=bx$

$x^2ac=x(xac)=x(acx)=bx\implies xacxx^{-1}=bxx^{-1}\implies xac=b$

$x(ac)(ac)^{-1}=b(ac)^{-1}\implies x=b(ac)^{-1}\implies x=bc^{-1}a^{-1}$

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\begin{cases}
n=\textit{last term}\\
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r=\textit{common ratio}
\end{cases}
\\ \quad \\
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