Question

Please help me graph

Answer 1

Answer:

From general linear equation;

${ \rm{y = mx + c}}$

m is the slope;

${ \rm{y = - \frac{1}{2}x + c }}$

• When x is -2 and y is 3;

${ \tt{3 = - (\frac{1}{2} \times - 2) + c}} \\ \\ { \tt{3 = 1 + c}} \\ { \tt{c = 2}}$

Therefore our line has equation of

${ \boxed{ \tt{y = - \frac{1}{2}x + 2 }}}$

OTHER POINTS.

${ \tt{ \red{ {1}^{st} \dashrightarrow \: (0, \: 2)}}}$

• ${ \rm{when \: x = 0, \: \: y = ( - \frac{1}{2} \times 0) + 2 }} \\ { \rm{y = 2}}$

${ \blue{ \tt{ {2}^{nd} \dashrightarrow \: (4, \:0) }}}$

• ${ \rm{when \: x = 4, \: \: y = ( - \frac{1}{2} \times 4) + 2 }} \\ { \rm{y = - 2 + 2 = 0}}$

${ \green{ \tt{ {3}^{rd} \dashrightarrow \: (6, \: - 1)}}}$

substitute for x as 6

Answer 2

Answer:

Get the y-intercept from (-2, 3) then get other points by considering one point at a time