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irina [24]
2 years ago
5

Equation to find three consecutive odd integers whose sum is 3

Mathematics
1 answer:
KiRa [710]2 years ago
8 0

The equation computed shows that the numbers will be 9, 11 and 13.

<h3>How to illustrate the information?</h3>

Let the numbers be:

First number = x

Second number = x + 2,

Third number = x + 4.

Total of the numbers = 33

The equation will be:

= first + second + third number

x + x + 2 + x + 4 = 33

3x + 6 = 33

Collect like terms

3x = 33 - 6

3x = 27.

Divide both side by 3

3x/3 = 27/3

x = 9

First number = x = 9

Second number = x + 2 = 9 + 2 = 11

Third number = x + 4. = 9 + 4 = 13

The numbers will be 9, 11, and 13.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

Illustrate the equation to find three consecutive odd integers whose sum is 33.

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Please help meeee ………..
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Step-by-step explanation:

The equality of bases property says powers of the same base will be equal if and only if the powers are equal. This property is used to solve exponential equations.

<h3>Application</h3>

  \dfrac{(2)^x}{2}=16\qquad\text{copy of the original equation}\\\\2\times\dfrac{(2)^x}{2}=2\times16\qquad\text{multiply by 2 to isolate the base}\\\\2^x=32\qquad\text{simplify}\\\\2^x=2^5\qquad\text{rewrite the constant as a power of 2}\\\\\boxed{x=5}\qquad\text{use the Equality of Bases Property}

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<em>Additional comment</em>

Equating the exponents is fully equivalent to taking the logarithm of both sides of the equation, to that base.

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