Question

Help me pleasee Questions r in picture

Answer 1

Answer:

$\large \bf\implies\frac{12}{61}$

Step-by-step explanation:

Given :

$\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...$

To Find :

• nth term

Solution :

We have to add 1 in numerator and -10 in denominator because

$\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]$

$\frac{8 \: + \: 1}{101 \: - \: 10} = \frac{9}{91} \\\\ \frac{9 + 1}{91 - 10} = \frac{10}{81} \\ \\ \frac{10 + 1}{81 - 10} = \frac{11}{71} \\ \\ \frac{11 + 1}{71 - 10} = \frac{12}{61} ...$

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.