Question

coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m across. when you leave the sandy patch your speed has been reduced to 6.5 m/s. assuming the bicycle slows with constant acceleration, what was its acceleration in the sandy patch?

Answer 1

Its acceleration in the sandy patch is $1.5 m/s^2$

Explanation:

The average speed

$V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s$

Time to pass patch

$t = 7.2 / 7.25 = .993 sec$

The acceleration

$a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2 or 1.5 m/s^2$

Hence,  $1.5 m/s^2$ that the acceleration in the sandy patch.

What do you understand by the acceleration?

Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

The meter per second per second (m/s2) unit of acceleration. Definition. The newton is the unit of force that, when applied to a mass of one kilogram, results in a one-meter-per-second acceleration.

Changing the speed at which an object is travelling is what acceleration is all about. A substance is not accelerating if its velocity is not changing.

To learn more about the acceleration, Visit: brainly.com/question/190239

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