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Westkost [7]
4 years ago
7

On December 26, 2004, a great earthquake occurred off the coast of Sumatra and triggered immense waves (tsunami) that killed som

e 200000 people. Satellites observing these waves from space measured 800 kmkm from one wave crest to the next and a period between waves of 1.0 hour. Part A What was the speed of these waves in m/sm/s
Physics
2 answers:
horrorfan [7]4 years ago
5 0

Answer:

The speed of these waves is 222.22 m/s

Explanation:

A.

Since, we know that the speed of a wave is given by the formula:

v = fλ

where,

v = speed of wave

f = frequency of wave

λ = wavelength

Here,

λ = distance between consecutive wave crests

λ = 800 km = 8 x 10⁵ m

f = 1/Time Period = (1/1 hr)(1 hr/3600 s)

f = 2.77 x 10⁻⁴ s⁻¹

Therefore,

v = (2.77 x 10⁻⁴ s⁻¹)(8 x 10⁵ m)

<u>v = 222.22 m/s</u>

FromTheMoon [43]4 years ago
5 0

Answer:

Explanation:

Given that,

200,000 people where killed due to earth quake in December 2004

Satellite observing measure a wavelength of 800km crest to crest

Crest to crest implies one wavelength

λ = 800km = 800,000m

Period of One hour

T = 1 hour = 3600s

Then, we want to find speed of wave.

Using wave equation

v = fλ

Where

f is frequency in Hz

v is speed of wave in m/s

λ is wavelength in m

Where f = 1 / T

Then, v = λ / T

v = 800,000 / 3600

v = 222.22 m/s

Then, the speed of the wave is 222.22 m/s

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