Answer:
(a) 1.08 m
(b) 1.06 m
Explanation:
<u>Step 1:</u> calculate the center of gravity from 20kg mass
Let the center of gravity from 20kg mass = X
Applying the principle of moment; clockwise moment = ant-clockwise moment
20*X = 35*(1.7-X)
20X = 59.5 - 35X
55X = 59.5
X = 59.5/55
X = 1.08 m
Ignoring the weight of the bar, the center of gravity is 1.08m from left end of the barbell.
<u>Step 2:</u> calculate the center of gravity from 20kg mass, if the 8.0kg mass of the barbell in considered.
Applying the principle of moment
20X +2.353X = 59.5 -35X + 4 - 2.353X
59.706X = 63.5
X = 63.5/59.706
X = 1.06 m
considering the weight of the bar, the center of gravity is 1.06m from left end of the barbell.
Answer:
A simple machine consisting of an axle to which a wheel is fastened so that torque applied to the wheel winds a rope or chain onto the axle, yielding a mechanical advantage equal to the ratio of the diameter of the wheel to that of the axle.
Hello!
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When objects are heated, their molecules tend to vibrate fast. As they vibrate, the space between each atom increases. This keeps on happening, and the object expands until it has cooled down.
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Hope this helps! :)
Answer:
Exercise 1;
The centripetal acceleration is approximately 94.52 m/s²
Explanation:
1) The given parameters are;
The diameter of the circle = 8 cm = 0.08 m
The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m
The speed of motion = 7 km/h = 1.944444 m/s
The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²
The centripetal acceleration ≈ 94.52 m/s²
Answer:
<h2>volume= 0.85m^3</h2>
Explanation:
<em>The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho</em>
Step one:
given data
we are told that the density of Co2= 1.98 kg/m3
and the mass of Co2 is= 1.70 kg
we know the relation between mass, volume and density is
make volume subject of formula we have
substitute we have
