Diffusion and osmosis are forms of passive transport. True False

Physics

2 answers:

pishuonlain [190]3 years ago

8 0

Answer:

True. Diffusion and osmosis are forms of passive transport.

Explanation:

In diffusion, particles move from an area of higher concentration to one of lower concentration until equilibrium is reached.

In osmosis, a semipermeable membrane is present, so only the solvent molecules are free to move to equalize concentration.

Elanso [62]3 years ago

7 0

Answer:

100% true

Explanation:

Simple diffusion and osmosis are both forms of passive transport and require none of the cell's ATP energy. Example of diffusion: Gas Exchange A biological example of diffusion is the gas exchange that occurs during respiration within the human body.

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The acceleration of an object (in m/s2) is given by the function a ( t ) = 6 sin ( t ) a(t)=6sin(t). The initial velocity of the

levacccp [35]

Answer:

$v(t)=-6cos(t)+4$

Explanation:

We have acceleration given by

$a(t)=6sin(t)$

Velocity at t = 0

$v(0)=-2\ m/s$

Velocity is given by

$v(t)=\int a(t)dt\\\Rightarrow v(t)=\int 6sin(t)dt\\\Rightarrow v(t)=6\int sin(t)\\\Rightarrow v(t)=-6cost+C$

at t = 0

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The equation will be

$\mathbf{v(t)=-6cos(t)+4}$

8 0

3 years ago

Read 2 more answers

You throw a rock straight up from the edge of a cliff. It leaves your hand at time t = 0 moving at 13.0 m/s. Air resistance can

Zarrin [17]

Answer:

0.36s, 2.3s

Explanation:

Let gravitational acceleration g = 9.81 m/s2. And let the throwing point as the ground 0 for the upward motion. The equation of motion for the rock leaving your hand can be written as the following:

$s = v_0t + gt^2/2$

where s = 4 m is the position at 4m above your hand. $v_0 = 13 m/s$ is the initial speed of the rock when it leaves your hand. g = -9.81m/s2 is the deceleration because it's in the downward direction. And t it the time(s) it take to get to 4m, which we are looking for