1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Greeley [361]
1 year ago
13

of the following and draw a neat, properly labelled free body diagram. Indicate the size of forces with the lengths of the arrow

s. i.e., if two forces are the same size draw them the same length and if one is much bigger draw it much longer. a) The Space Shuttle accelerating vertically just after leaving the launch pad.
Physics
1 answer:
julsineya [31]1 year ago
4 0

We will have that the diagram will be the following:

Here "F" is the force the shuttle is using to take off, friction is the friction with the air and "W" is the weight of the shuttle.

You might be interested in
Two conducting spheres of different sizes are at the same potential. The radius of the larger sphere is four times larger than t
Sergeeva-Olga [200]

Answer:

0.8

Explanation:

The two spheres have the same potential, V.

Let the radius of the larger sphere be R and the radius of the smaller sphere be r,

=> R = 4r

Let the charge on the smaller sphere be q. Hence, the larger sphere will have charge Q - q.

The potential of the smaller sphere will be:

V_S = \frac{kq}{r}

The potential of the larger sphere will be:

V_L = \frac{k(Q - q)}{R}

Inputting R = 4r,

V_L = \frac{k(Q - q)}{4r}

Since V_S = V_L = V,

\frac{k(Q - q)}{4r} = \frac{kq}{r}

=> Q - q = 4q

=> 5q = Q

q = 0.2Q

The fraction of the charge Q that rests on the smaller sphere is 0.2

The charge of the larger sphere is:

Q - q = Q - 0.2Q = 0.8Q

∴ The fraction of the total charge Q that rests on the larger sphere is 0.8

7 0
3 years ago
A box sits on a table. A short arrow labeled F subscript N points up. A short arrow labeled F subscript g points down. A long ar
Aloiza [94]

Answer:

unbalanced and right

Explanation:

7 0
3 years ago
What is a good hypothesis when putting pop rocks into soda?
8_murik_8 [283]
That it will erupt upon contact. Hope it helps!
6 0
3 years ago
3. Si usted duplicara la amplitud de un M.A.S. ¿cómo cambiaría la frecuencia, velocidad máxima, la aceleración máxima y la energ
WITCHER [35]

Answer:

Explanation:

la frecuencia = ω/2π, nada cambio

v(max) = ωA → ω2Α = 2ωA  duplicara velocidad máxima

a(max) = ω²Α → ω²2Α = 2ω²Α duplicara la aceleración máxima

la energía total ½kA² → ½k(2Α)² = 4(½kA²) cuatro veces la energía

8 0
3 years ago
Describe streak and cleavage and explain how they can be used to identify a mineral. PLEASE HELP.
timofeeve [1]
Streak means continuously
5 0
4 years ago
Read 2 more answers
Other questions:
  • You serve a volleyball with a mass of 2.1 Kg. The ball leaves your hand with a speed of 30m/s. The ball has __________________ e
    9·1 answer
  • A 5.0-kg clay putty ball and a 10.0-kg medicine ball are headed towards each other. Both have the same speed of 20 m/s. If they
    15·1 answer
  • If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu
    5·2 answers
  • Two asteroids are 50,000 m apart. one has a mass of 5 x 10^8 kg. If the force of gravity between them is 8.67 x 10 ^ -2 N, what
    8·2 answers
  • Consider a coil lying in the plane of the screen and the external magnetic field pointing into the screen. As the external magne
    10·1 answer
  • What is the net displacement of the particle between 0 seconds and 80 seconds
    9·1 answer
  • The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, an
    6·1 answer
  • What is gravity???☺️<br>​
    5·2 answers
  • Sense an ion is an atom does it have a negative charge?
    5·1 answer
  • What is the acceleration of a car that goes from 4m/s to 8m/s in 2s use the guess method​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!