1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
victus00 [196]
3 years ago
15

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

glish and 95 are fluent in both languages. What is the probability that a student chosen at random is fluent in english or swahili.
Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

You might be interested in
What is the value of g?<br> −5+7g=3g+9<br> A.) g=−1<br> B.) g = 1<br> C.) g=125<br> D.) g=312
Whitepunk [10]

Answer:

The answer is D

Step-by-step explanation:

Give the other person brainlest

6 0
3 years ago
Read 2 more answers
Complete the following statement. A fraction in lowest terms is in its __________________________________
pantera1 [17]

Answer:

Reduced form

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
8) Factor each sum or difference of cubes completely.<br> a. 8x3 + 27
ASHA 777 [7]

Answer:

\large\boxed{(2x+3)(4x^2-6x+9)}

Step-by-step explanation:

8=2^3\\\\8x^3=2^3x^3=(2x)^3\\\\27=3^3\\\\8x^3+27=(2x)^3+3^3\qquad\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+3)\bigg((2x)^2-(2x)(3)+3^2\bigg)=(2x+3)(4x^2-6x+9)

4 0
3 years ago
What is the solution to the equation −p − 13 = −4 /3 p + 2/3 ( 5p − 6 ) ?
jekas [21]

Answer:

The answer is p= 2 and 1/3

Step-by-step explanation:

This answer can be found using the order of operations to solve for p.

Start by distributing 2/3 by (5p-6)

add -4/3p to 10/3p equaling 6/3p or 2p

subtract 13 from both sides

-p= 2p - 7

p=2 and 1/3

3 0
2 years ago
Help please I feel stupid
deff fn [24]

Answer:

44

Step-by-step explanation:

h(-7) means use the expression labeled h and evaluate it for x=-7.

Like this:

(-7)^2 - 5

49 - 5

44

3 0
3 years ago
Other questions:
  • &lt;&lt;&lt; HERE IT IS HELP AND STAY IF U CAN
    9·1 answer
  • HELP PLEASE BE QUICK
    10·2 answers
  • What happens when the scale factor is less than 1? What happens when the scale factor is greater than 1?
    7·2 answers
  • A student expanded an expression, as shown. Is the student's work correct? Explain why or why not.
    13·2 answers
  • Which expression is equivalent to 5^10 times 5^5?
    5·1 answer
  • For each relation, decide whether or not it is a function.<br>​
    6·1 answer
  • Ava's mom purchased a savings bond for Ava. The value of the savings bond increases by 3% each year. One year after it was purch
    13·1 answer
  • PLZ HELP AND HURRY!!!!
    12·1 answer
  • QuestionUse the Distributive Property to simplify the expression.9(3+c+4) =
    14·1 answer
  • Audrey has $440 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!