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N76 [4]
3 years ago
14

PLS HELP WILL GIVE BRAINLIEST!! Identify this set of lines as parallel, perpendicular, or neither.

Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

Neither

It isnt parallel or perpendicular.

You can use the Desmos website to input these lines so you have a visual representation.

shutvik [7]3 years ago
6 0

Answer: Perpendicular

Step-by-step explanation:

This is perpendicular since the slopes of the angles Intercept each other

given by the slope.

Since the lines have opposite reciprocals ( slope ) they are perpendicular.

Meaning the slope Is flipped.

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The lengths of the sides of a square are represented by the expression 3x + 1 cm. The perimeter of the square is 28 cm. What is
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Answer:

x=2

Step-by-step explanation:

Perimeter of a square = 4*(side of the square)

28 = 4*(3x+1)

28 = 12x + 4

28- 4 = 12x

24 = 12x

x =2

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3 years ago
What is the greatest common factor of 28x²y-7xy^5?
Alchen [17]
The greatest common factor of this can be solved by looking at the individual parts and splitting it up.

First, we have 28 and 7.  Well, thats an easy one.  7 goes into 28 4 times so we are now left with 4 and 1.

We can also write the rest of this like this 4(x*x*y) - 1(x*y*y*y*y*y)

Now, what values are in both equations.  We have one x and one y that can be taken out of both.

We end up with 7xy(4x-7y^4)
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3 years ago
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Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me
Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean \mu and standard deviation s = \sqrt{n}*\sigma

In this problem, we have that:

\mu = 11.5, \sigma = 4

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have n = 50, s = \frac{4}{\sqrt{50}} = 0.5657

This probability is 1 subtracted by the pvalue of Z when X = 12.

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{12 - 11.5}{0.5657}

Z = 0.88

Z = 0.88 has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28

This probability is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 575}{28.28}

Z = 0.88

Z = 0.88 has a pvalue of 0.8106.

81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c. What is the approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers.

This is X when Z has a pvalue of 0.95. So it is X when Z = 1.645.

Z = \frac{X - \mu}{s}

1.645 = \frac{X- 575}{28.28}

X - 575 = 28.28*1.645

X = 621.5

The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

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