Question

Two parallel wires separated by 4.00cm repel each other with a force per unit length of 2.00×10⁻⁴ N/m . The current in one wire is 5.00 A. (c) What would happen if the direction of one current were reversed and doubled?

Answer 1

The force will be doubled if direction of one current is reversed and doubled.

The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.

With a distance of 4.00 cm between them, two parallel wires repel one another with a force of 2.00 × 10⁻⁴ N/m. One wire is carrying 5.00 A of current.

I₁ = 5 A

d = 4 cm

F = 2 × 10⁻⁴ N/m

We have, F/L = μ₀ I₁ I₂ / L

Now, we know the force is directly proportional to the product of the current, and the direction of one current is reversed and doubled.

The force of interaction would become attractive and its magnitude would double as a result of switching the directions of either of the currents and doubling their size.

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