Answer:
N
Explanation:
Using the formula you gave:

•Independent: different color sand samples
•Dependent: temperature of the sand
•Control/constant (means the same thing) : Same containers, same time in sun, same thermometer
Answer: 588.9 m/s
Explanation:
Given that :
θ = 30°
Height, h = 3400m
Time, t = 10 seconds
From trigonometry ;
Tanθ = opposite / hypotenus
Tan 30 = 3400 / x
x tan 30 = 3400
0.5773502x = 3400
x = 3400 / 0.5773502
x = 5888.9727
Recall ;
Speed = Distance / time
Speed = 5888.9727 / 10
Speed = 588.897 m/s
Speed = 588.9 m/s
Answer:
t = 2 v₀ / g
Explanation:
For this projectile launch exercise we use the displacement equations
x = vox t
y = y₀ +
t - ½ g t²
As it is launched horizontally the vertical velocity is zero and the point of origin of the coordinate system is here, so y₀ is zero.
x = v₀ t
y = ½ g t²
They ask us for the time for which
x = y
vo t = ½ g t²
t = 2 v₀ / g