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Elanso [62]
3 years ago
15

Dr. Lopez is Thomas's doctor. During his appointment, Thomas says he thinks

Physics
1 answer:
alukav5142 [94]3 years ago
8 0

A. Conduct an exam. Thomas might have a drug dependence.

(Please mark Brainliest! :D)

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Your answer would be 4.0 hz.
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What is the speed of a giraffe that has a
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4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc
muminat

a) 15.2 m/s^2

b) 1.96 N

c) 1.96 N

Explanation:

a)

To find the acceleration of the box, we apply Newton's second law of motion:

\sum F=ma

where

\sum F is the net force on the box

m is the mass of the box

a is its acceleration

Here we have to consider the horizontal direction, which is the one in which the box is moving. The net force is given by:

\sum F=3.55 N - 0.52 N=3.03 N

which is the difference between the forward force and the resistive force. Then we have

m = 0.200 kg (mass of the box)

Therefore, the acceleration of the box is:

a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2

b)

The gravitational force (also called weight) is the force with which an object is pulled by the Earth towards the Earth's centre.

It is given by

F_g = mg

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

m = 0.200 kg is the mass of the box

g=9.8 m/s^2 is the acceleration due to gravity

Therefore, the gravitational force on the box is:

F_g=(0.200)(9.8)=1.96 N

c)

The normal force is the force with which a surface pushes back on an object.

For an object lying on a flat surface, there are two forces acting along the vertical direction:

- The gravitational force, F_g, which pushes the object downward

- The normal force, N, which pushes the object upward

As the object is at rest, the vertical acceleration of the object is zero, therefore according to Newton's second law of motion, the net force must be zero:

\sum F=F_g-N=0

Which means that the normal force is equal to the gravitational force:

N=F_g

And so, for the box in this problem, the normal force is

N=1.96 N

6 0
4 years ago
An experiment on the earth's magnetic field is being carried out 1.00 m from an electric cable. What is the maximum allowable cu
Whitepunk [10]

Answer:

The allowed current in the cable is 1.15 A.

Explanation:

Given that,

Distance = 1.00 m

Suppose the magnetic field is 2.3\times10^{-5}\ T and  if the experiment is to be accurate to 1.0 %

We need to calculate the current

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu_{0}}

Put the value into the formula

I=\dfrac{2.3\times10^{-5}\times2\times\pi\times1.00}{4\pi\times10^{-7}}

I=115\ A

If the experiment is to be accurate to 1.0%

Then,

We need to calculate the allowed current in the cable

I'=(1.0%)\times I

I'=\dfrac{1.0}{100}\times115

I'=1.15\ A

Hence, The allowed current in the cable is 1.15 A.

4 0
3 years ago
Why is that the hunter can not aim at the fish he can see
poizon [28]

Answer: Because the hunter will try to aim at the fish, but the image of fish he sees is actually the apparent image of the fish at a location.

Heres an image to help

Hope this helps!

6 0
3 years ago
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