Find the cumulative frequency

Mathematics

1 answer:

aleksandrvk [35]10 months ago

5 0

We get the cumulative frequency as:

We are given the data:

Daily Low(°F) Frequency

35 - 39 3

40 - 44 4

45 - 49 6

50 - 54 9

55 - 59 7

60 - 64 7

65 - 69 1

We have to find the cumulative frequency of the data.

We will do this by adding the data values of previous interval.

Daily Low(°F) Frequency cumulative frequency

35 - 39 3 3

40 - 44 4 7

45 - 49 6 13

50 - 54 9 22

55 - 59 7 29

60 - 64 7 36

65 - 69 1 37

Therefore, we get the cumulative frequency as:

Learn more about cumulative frequency here:

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How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

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According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$