By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
#SPJ1
Here is how you find the answer.
Do remember that the term Bisect means to cut it in half.
So here it goes.
<span>5x = 3x + 10
5x - 3x = 10
2x = 10
x = 5
Then, substitute the values, so 5*5 or 3*5+10
Then, the answer for each smaller angle is 25.
</span>Remember bisect? so 25 x 2 so the final answer is 50.
Hope this is the answer that you are looking for. Thanks for posting your question!
hi you could use Google Translate or even a dictionary when you see the diagram of a speaker pls mark braiest and follow me
Answer: The answer is 
ounces.
Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:
We can see that
So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:
Thus, the weight of the puupy after 3 weeks will be
Answer:
The cost function for 
is 
.
Step-by-step explanation:
The marginal cost function (
) is the derivative of the cost function (
), then, we should integrate the marginal cost function to find the resulting expression. That is:
Where:
- Fixed costs, measured in US dollars.
If we know that and 
, then:
The cost function for is .
