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DENIUS [597]
3 years ago
14

How do we express one-half of thedifference of a number cubed and one?​

Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:the number one

Step-by-step explanation:

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There are 27 pupils. There are twice as many boys than girls. how many boys and girls are there
Anna71 [15]
Let x  =  the numbers of girls
thus
the numbers of boys  = 2x 
x + 2x = 27
3x = 27
x = 9
2x = 2 . 9 =18
girls  =  9  &  boys  = 18
3 0
3 years ago
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What is the quotient of 74.75 and 10 to the second power?
Semmy [17]
10 to the second power=100
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3 years ago
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Write an appropriate direct variation equation if y = 18 when x = 2
Sergeu [11.5K]

Answer:

y=9x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem we have

y=18 when x=2

Find the value of the constant of proportionality k

k=\frac{y}{x} ----> k=\frac{18}{2}=9

therefore

The equation is equal to

y=9x

8 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
Math - algebra (9th grade) please include work
Naily [24]

Answer:

Step-by-step explanation:

Y)  \frac{x+4}{8} = 3

*multiply both sides by 8 - cancels out 8 in denominator*

x + 4 = 24

*subtract 4 from both sides*

x = 20

E) \frac{x-5}{2} = 1

*multiply both sides by 2 - cancels out 2 in denominator*

x - 5 = 2

*add 5 on both sides*

x = 7

N) \frac{x+2}{4} = 2

* multiply both sides by 4 - cancels out 4 in denominator*

x + 2 = 8

*subtract 2 from both sides*

x = 6

3 0
3 years ago
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