The heat capacity of iron is 0.45J/g°C.
We calculate the heat using the equation:
ΔH = m cp ΔT
where
<span>m is the mass
ΔH is enthalphy or the heat required
cp is the heat capacity
</span><span>ΔT is the change in temperature
</span>So,
<span>ΔH = m cp ΔT = (125g) (0.45 J/g</span>°C) (75°C - 23.5<span>°C)
</span><span>ΔH = 2896.875 J
</span>
Dividing by 1000 to convert to kJ,
<span>ΔH = 2.897 kJ</span>
Answer: H2O (water)
Explanation:
The answer choices for this question are:
A) H2O
B) N2
C) SO2
D) NO3
E) Cl2
The solution of the problem is:
1) Data:
<span> density, d = 1.4975 g/liter
volume, V = 8.64 liter
pressure, p = 2.384 atm
temperature, T = 349.6 K
2) Formulas:
d = m/V => m = d*V
n = m / molar mass => molar mass = m / n
pV = nRT => n = pV / RT
3) Solution
n = pV / RT = 2.384 atm * 8.64 liter / (0.0821 atm*liter/K*mol * 349.6K)
n = 0.7176 moles
</span>m = dV = 1.4975 g/ liter * <span>8.64 liter = 12.9384 g
molar mass = m / n = 12.9384 g / 0.7176 moles = 18.03 g/mol
That molar mass corresponds to the molar mass of water, therefore the gas is H2O (water vapor).</span>
Answer:
t = 125.3 seconds
Explanation:
Molar mass of CO2 = 12+2(16) = 66
Molar mass of N2 = 2(14)= 28
rate of diffusion of N2 = volume/ time = 280cm³/70s
= 4cm³/s
let rate of CO2 = rate of diffusion of CO2 = volume/time
= 400/t
Using Graham's law of diffusion,
rN2/rCO2 = √M(CO2)/M(N2)
4/400/t =√44/28 = 4t/400= √11/7
t/100 = 1.253 , t= (100)(1.253)
t = 125.3 seconds
hence it takes CO2 125.3 seconds to diffuse through the membrane
