Calculate each of the following quantities: (b) Amount (mol) of compound in 15.8 kg of Fe(ClO₄)₃

Chemistry

1 answer:

kotykmax [81]2 years ago

8 0

The amount (mol) of the compound in 15.8 kg of Fe(ClO₄)₃ is 0.044 moles.

The mole is the smallest unit of the atom which use to represent how many atoms moles or molecules are used in a chemical process or in a chemical reaction which is always equal to 2.303 ×10²³ moles for one atom.

To calculate the mass of 0.68 mol of KMnO₄ the formula will use is,

number of moles = mass / molar mass

molar mass of Fe(ClO₄)₃ = 354.19

mass of Fe(ClO₄)₃ = 15.8kg

substituting the value in the equation,

number of moles = 15.8kg / 354.19

number of moles = 0.044 moles

Therefore, 0.044 moles is the amount (mol) of the compound in 15.8 kg of Fe(ClO₄)₃.

Learn more about moles, here:

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