Answer:
295.7 mL of 24% trichloroacetic acid (tca) is needed .
Explanation:
Let the volume of 24% trichloroacetic acid solution be x
Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces
= 24 ounces = 709.68 mL
(1 ounces = 29.57 mL)
Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.
x = 295.7 mL
295.7 mL of 24% trichloroacetic acid (tca) is needed .
Answer:
The easiest way to identify a double displacement reaction is to check to see whether or not the cations exchanged anions with each other.
Explanation:
if the states of matter are cited, is to look for aqueous reactants and the formation of one solid product (since the reaction typically generates a precipitate).
T=2T
m=10 g
m=m₀2^(-t/T)
m₀=m/{2^(-2T/T)=m/2⁻²
m₀=10/2⁻²=40 g
40 grams
They are hard solid with a crystal lattice structure... with high melting points
Https://www.coursehero.com/tutors-problems/Chemistry/9952231-Draw-the-Lewis-structure-for-Li2S-Rb2S-...
