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3 years ago

I have 4 factors. three are 1, 2, and 10. what is the fourth

Mathematics

2 answers:

jeka943 years ago

7 0

The greatest factor of any number is the number itself.
So you are the number 10, and the missing factor is 5.

Alina [70]3 years ago

3 0

I think that the missing factor is five

Correct me if im wrong

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How do i turn factions to decimals? Such as 2/7 written as a decimal is:

arlik [135]

0.28

2 divided by 7 is 0.28

All you have to do is divide the numerator by the demoninator in order to get your decimal.

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3 years ago

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The Wilsons have triplets and another child who is eleven years old. The sum of the ages of their children is 32. How old are th

Leno4ka [110]

ANSWER:

The triplets will be 7 years each. 21, divided by 7.

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3 years ago

Vance is designing a garden in the shape of an isosceles triangle. The base of the garden is 30 feet long. The function y = 15 t

Stella [2.4K]

Answer:

A. 8.66 feet

B. 12.59 feet

C. Area of triangle when $\theta=30$ is 129.9 square feet. Area of triangle when $\theta=40$ is 188.85 square feet. Increasing the angle $\theta$ increases the area.

Step-by-step explanation:

The equation that models the height of the triangle is:

$y=15 Tan \theta$

Where,

$y$ is the height, and

$\theta$ is the angle

When $\theta=30$ , the height is:

$y=15Tan30\\y=8.66$

B. When $\theta=40[/tex\ , the height is:[tex]y=15Tan40\\y=12.59$

C. To find the area of the isosceles triangular shaped garden, we use the formula for the area of the triangle:

$A=\frac{1}{2}bh$

Where,

A is the area
b is the base, which is given as 30 feet, and
h is the height [8.66 feet when the angle is 30 & 12.59 when angle is 40]

When Vance uses $\theta=30$ , the area is:

$A=\frac{1}{2}(30)(8.66)\\A=129.9$ square feet

When Vance uses $\theta=40$ , the area is:

$A=\frac{1}{2}(30)(12.59)\\A=188.85$ square feet

So we see that when the angle is more, the area is also more.

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3 years ago

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Answer:

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3 years ago

Find the sum of -3a and 5a -3

zepelin [54]

Find the sum of -3a and 5a -3

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2a-3

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4 years ago