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2 years ago

Why is the Arrhenius acid-base definition too limited? Give an example for which the Arrhenius definition does not apply.

1 answer:

6 0

Arrhenius theory is the most limited acid-base definition because it only applies to acids and bases with H + H^+ H+ and O H − OH^- OH−

<h3>What is Arrhenius theory?</h3>

The hydrogen ion (H+) is one of the electrically charged atoms or molecules that are produced when an acid dissociates in water, according to the Arrhenius theory, which was first proposed by the Swedish scientist Svante Arrhenius in 1887. On the other hand, bases ionize in water to produce hydroxide ions (OH). It is now understood that in a solution of water, the hydrogen ion cannot exist alone but rather coexists with a water molecule to form the hydronium ion (H3O+). The hydrogen ion is still the common name for the hydronium ion in everyday speech.

The basic characteristics of well-known hydroxides and the acidic behavior of numerous well-known acids, including sulfuric, hydrochloric, nitric, and acetic acids

To learn more about Arrhenius theory from the given link:

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An electron charge e mass m and a positron charge e mass m revolve around their common center of mass under the influence of the

Katen [24]

Answer: v = 2π2 Kme2 Z / nh

Explanation:

The formula for velocity of an electron in the nth orbit is given as,

v = 2π2 Kme2 Z / nh

v = velocity

K = 1/(4πε0)

m= mass of an electron

e = Charge on an electron

Z= atomic number

h= Planck’s constant

n is a positive integer.

3 0

4 years ago

One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet

PSYCHO15rus [73]

Answer:

$2.4*10^{7}cm^{3}$

Explanation:

First you should calculate the volume of a big sphere,so:

$V_{big}=\frac{4}{3}\pi r^{3}$

$V_{big}=\frac{4}{3}\pi (181cm)^{3}$

$V_{big}=2.4*10^{7}cm^{3}$

Then you calculate the volume of a small spehre, so:

$V_{small}=\frac{4}{3}\pi r^{3}$

$V_{small}=\frac{4}{3}\pi (5.01cm)^{3}$

$V_{small}=5.3*10^{2}cm^{3}$

Finally you subtract the two quantities:

$V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}$

$V_{big}-V_{small}=2.4*10^{7}cm^{3}$

5 0

3 years ago

What volume of H2 at STP, can be released by 42.7 g Zn in the equation: Zn + 2 HCl ————> H2 + ZnCl2

ehidna [41]

Answer:

0.86L.

Explanation:

1mol of Zn has mass of 65.39g . The amount of Zn is 2.5g65.39g/mol=0.038mol

7 0

2 years ago

HELP......Percussion instruments are musical instruments that make noise when they are hit with an object. Which of these are pe

valkas [14]

Answer:

I believe that the percussion instruments are the drum and cymbal.

Explanation:

4 0

4 years ago

KOH (aq) + HNO(little3) (aq) = KNO(little 3) (aq) + H20 (1)

Yuki888 [10]

The reaction already balanced

<h3>Further explanation </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C, H and the last O

Reaction

KOH (aq) + HNO₃ (aq) ⇒ KNO₃ (aq) + H₂0 (l)

give coefficient

aKOH (aq) + bHNO₃ (aq) ⇒ KNO₃ (aq) + cH₂0 (l)

K : left = a, right = 1⇒a=1

N : left = b, right =1, b=1

H: left = a, right a+b=2c⇒1+1=2c⇒2=2c⇒c=1

KOH (aq) + HNO₃ (aq) ⇒ KNO₃ (aq) + H₂0 (l)⇒ already balanced

5 0

3 years ago