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bixtya [17]
2 years ago
8

Sodium chloride or table salt is a compound formed when sodium loses its valence electron to chlorine. Which type of bond format

ion takes place in sodium chloride?
Chemistry
2 answers:
avanturin [10]2 years ago
8 0

When Sodium chloride or table salt is a compound formed when sodium loses its valence electron to chlorine, the type of bond formation that takes place in sodium chloride is the Lewis Bond.

Sedaia [141]2 years ago
7 0

Answer:

ionic bond

Explanation:

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Mn+2 is cation and CO3 is anion
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A sample of gas initially has a volume of 2.25 L at 350 K and a pressure of 1.75 atm. What will be sample pressure if the volume
IRINA_888 [86]

Answer:

8.44 atm

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2.25 L

Initial temperature (T₁) = 350 K

Initial pressure (P₁) = 1.75 atm

Final volume (V₂) = 1 L

Final temperature (T₂) = 750 K

Final pressure (P₂) =?

The final pressure of the gas can be obtained as illustrated below:

P₁V₁/T₁ = P₂V₂/T₂

1.75 × 2.25 / 350 = P₂ × 1 / 750

3.9375 / 350 = P₂ / 750

Cross multiply

350 × P₂ = 3.9375 × 750

350 × P₂ = 2953.125

Divide both side by 350

P₂ = 2953.125 / 350

P₂ = 8.44 atm

Thus, the final pressure of the gas is 8.44 atm.

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3 years ago
Lead has a density of 11.4 g/cm^3. What is the density in kilograms per cubic meter?
Vikentia [17]

The density in kg/m³ = 1.14 x 10⁴

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density , g/cm³ or kg/m³  

m = mass  , g or kg

v = volume  , cm³ or m³  

A density of Lead : ρ = 11.4 g/cm³

the density in kg/m³ :

\tt 11.4~\dfrac{g}{cm^3}\times \dfrac{kg}{10^3~g}\times \dfrac{cm^3}{10^{-6}~m^3}=\boxed{\bold{1.14\times 10^4~\dfrac{kg}{m^3}}}

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