Question

Solve the following system of equations. 2x+3y=1 5x-4y=14 (See picture attached)

Answer 1

Answer: solving the first equation for

x

:

substracting

3

y

2

x

=

1

+

3

y

dividing by

2

we get

x

=

1

2

+

3

2

y

plugging this in the second equation

5

(

1

2

+

3

2

y

)

+

4

y

=

14

multiplying by

2

5

(

1

+

3

y

)

+

8

y

=

28

5

+

15

y

+

8

y

=

28

collecting like Terms

23

y

+

5

=

28

substracting

5

and dividing by

23

y

=

1

so we get

x

=

1

2

+

3

2

=

4

2

=

2

Answer 2

The solution to the system of equations is x = -1 and y = -1

How to solve the following system of equations?

The system of equations is given as:

2x + 3y = 1

5x - 4y = 14

Multiply 2x + 3y = 1 by 2.5

So, we have:

5x + 7.5y = 2.5

Subtract 5x + 7.5y = 2.5 from 5x - 4y = 14

So, we have

7.5y + 4y = 2.5 - 14

Evaluate the difference and the sum

11.5y = -11.5

Divide by 11.5

y = -1

Substitute y = -1 in 2x + 3y = 1

2x + 3(1) = 1

This gives

2x + 3 = 1

Subtract 3

2x = -2

Divide by 2

x = -1

Hence, the solution to the system of equations is x = -1 and y = -1

Read more about  system of equations at

brainly.com/question/14323743

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