Given:
and 
.
To find:
The value of f(5).
Solution:
We have,
For 
,
For 
,
For 
,
For 
,
Therefore, the value of 
is 
.
Answer:
-12/5 - 2
Step-by-step explanation:
-18÷3×8(-8)/-5×-2+(-2) =
-6×8(-8)/-5×-2+(-2) =
-48(-8)/-5×-2+(-2) =
6/-5×-2+(-2) =
-12/5 - 2
Answer:
perimeters of the rectangle=p=46.014 metres
Step-by-step explanation:
Given that:
Length (l) = 21 m
Area of rectangle(A) = 42.15 meter-square
Width (w)=?
Required data:
Perimater of Rectangle=p=?
Calculation:
As we know that Area of rectangle=A=l*w
Putting the value we get
42.15 m(square)=(21 m)*w
or w=42.15/21
or w=2.007 m
Now to find perimters of rectangle we know that
p=2(l + w) metres
putting the values
p=2(21+2.007) metres
p=2(23.007) metres
p=46.014 metres
Answer:
Step-by-step explanation:
we know that
The volume of the composite figure is equal to the volume of a semi-sphere plus the volume of the cone
so
we have
substitute
Answer:
Sum is - 5n² -8n + 4.
Step-by-step explanation:
Given : (3n² – 5n + 6) + (–8n²– 3n – 2) .
To find : Sum .
Solution : We have (3n² – 5n + 6) + (–8n²– 3n – 2) .
Combine like terms :
(3n² - 8n²– 5n - 3n + 6 - 2).
- 5n² -8n + 4.
Therefore, Sum is - 5n² -8n + 4.
