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Basile [38]
2 years ago
15

I have only 10 points plus give me the right answer this is the last I’m gonna ask but pls help just answer the blank question

Mathematics
1 answer:
marusya05 [52]2 years ago
7 0

15

I guess so

Hope it is correct

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Points ), K and L are collinear with J between L and K. IF KJ = 28 - 3, LK = 9x + 7 and LJ = 4x - 8,
babymother [125]

J, K, and L are collinear

J is between K and L

LK = KJ + LJ

LK = 9x + 7

KJ = 2x - 3

LJ = 4x - 8

9x + 7 = (2x - 3) + (4x - 8)

9x + 7 = (2x + 4x) + (-3 - 8)

9x + 7 = 6x + -11

9x + 7 = 6x - 11

9x + 7 - 7 = 6x - 11 - 7

9x = 6x - 18

9x - 6x = 6x - 6x - 18

3x = -18

x = -6

∴ The value of x is -6

6 0
2 years ago
Four gallons of gasoline cost $16.80. What is the price per gallon (also known as the slope of the line)?
il63 [147K]

$16.80 / 4 gallons = $4.20 per gallon

5 0
3 years ago
A circle has a radius of 7 cm. Workout the area of the circle. Give your answer correct to three significant figures.
anastassius [24]

Answer:

πr²=22/7×49

=22×7

=154

hope it helps

Mark me brainliest

5 0
3 years ago
Suppose you deposited $10 into your savings account each month, as indicated in the table. Your account pays 4%, compounded mont
Orlov [11]
I think its D. $1,800 because 10.4 multiplied by twelve is 124.8 and if you multiply that by 15 you get $1.872. 
4 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
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