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anzhelika [568]
1 year ago
13

What is this question in simplified form

Mathematics
1 answer:
EastWind [94]1 year ago
6 0

Answer: -77\sqrt{30}

Step-by-step explanation:

(-7(3)^1/2)(11(10)^1/2)=

-7*11*(3)^1/2 * (10)^1/2=

-77*(3*10)^1/2=

-77(30)^1/2=-77\sqrt{30}

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Simplify the expression
ollegr [7]

Answer:

<h3>              f(x) = x - 6</h3><h3>             g(x) = x - 5</h3>

Step-by-step explanation:

\dfrac{x^2-8x+12}{x^2-7x+10}\\\\x^2-7x+10\ne0\ \iff\ x=\frac{7\pm\sqrt{49-40}}{2}\ne0\ \iff\ x\ne5\ \wedge\ x\ne2\\\\\\\dfrac{x^2-8x+12}{x^2-7x+10}=\dfrac{x^2-2x-6x+12}{x^2-2x-5x+10}=\dfrac{x(x-2)-6(x-2)}{x(x-2)-5(x-2)}=\\\\\\ =\dfrac{(x-2)(x-6)}{(x-2)(x-5)}=\dfrac{x-6}{x-5}\\\\\\f(x)=x-6\\\\g(x)=x-5

4 0
3 years ago
Volume of a cube is 343 cm cube . find the edge​
Charra [1.4K]

Answer:

d

Step-by-step explanation:

d

6 0
3 years ago
Read 2 more answers
Solve each compound inequality<br><br> 10m &gt; 84
Mazyrski [523]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's solve :

  • 10m > 84

  • m >  \dfrac{84}{10}

  • m > 8.4
6 0
3 years ago
I'm really confused, can someone please help me with this problem?
stiv31 [10]

Answer: x = 6.25

5 ÷ 0.8

= 6.25

6 0
3 years ago
Please help me out with this so I can keep my kitten.
notka56 [123]

Answer:

y = \frac{32}{3}

Step-by-step explanation:

Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):

\frac{y}{8} = \frac{7}{12}  + \frac{3}{4}

Now, to add the two fractions, simply multiply the numerator and denominator by 3:

\frac{3*3}{4*3} = \frac{9}{12}

Now add this to the other fraction:

\frac{9}{12} + \frac{7}{12} = \frac{16}{12}

This can be simplified down by dividing both the numerator and denominator by 4:

\frac{4}{3}

Which now simplifies the original equation to:

\frac{y}{8}  = \frac{4}{3}

Remove the y out of the fraction:

\frac{1}{8}y = \frac{4}{3}

Now multiply both sides by 8:

(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8

y = \frac{4*8}{3}

y = \frac{32}{3}

Hope this helps!

5 0
3 years ago
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