Lee’s family had a garden in the shape of a right triangle. The total area of the garden is 16 square feet. If they expand the g
1 answer:
You might be interested in
Answer:
(- 2, 6 )
Step-by-step explanation:
Given the equations
3x + 2y = 6 → (1)
y - x = 6 ( multiply through by 3 to clear the fraction )
2y - 3x = 18 ( add 3x to both sides )
2y = 18 + 3x → (2)
Substitute 2y = 18 + 3x into (1)
3x + 18 + 3x = 6
6x + 18 = 6 ( subtract 18 from both sides )
6x = - 12 ( divide both sides by 6 )
x = - 2
Substitute x = - 2 into (1) and solve for y
3(- 2) + 2y = 6
- 6 + 2y = 6 ( add 6 to both sides )
2y = 12 ( divide both sides by 2 )
y = 6
solution is (- 2, 6 )
The approximate area of the park on the grid is: E. about 40 km² to 50 km².
<h3>How to Find the Approximate Area on a Coordinate Grid?</h3>The number of square on a coordinate grid that is covered determines the area covered. We can make an estimate by counting how many of this square on the coordinate grid that is covered, then find out the area depending on how much square area each grid represents.
In the coordinate plane given, which shows a park, we are told that each of the square on the grid equals 1 k = square kilometer.
The number of each of these squares we can find that is covered by the park on the grid is: 48 squares.
Therefore, the area of 48 squares on the grid = 48 × 1 = 48 km². Since not all squares are fully covered by the park, we can state that the approximate area of the park on the grid is: E. about 40 km² to 50 km².
Learn more about the approximate area on a grid on:
#SPJ1
Answer:
9.14 inches.
Step-by-step explanation:
From the question,
Assuming the diagram attached, is similar to diagram required to support the question,
From the diagram,
Applying pythagoras theorem
a² = b²+c²...................... Equation 1
Where a = 13.4 in, b = x in, c = 9.8 in.
Substitute these values into equation 1
13.4² = x²+9.8²
x² = 13.4²-9.8²
x² = 179.56-96.04
x² = 83.52
x = √(83.52)
x = 9.14 inches
Hence the distance between the rods is 9.14 inches
