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OleMash [197]
3 years ago
9

Can someone please help me find C? Thank you :)

Mathematics
1 answer:
gulaghasi [49]3 years ago
3 0
I think it's a, c or e since those are all close to ten but you could use a ruler
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Use the given information to solve the triangle for A = 150°, b = 4.8, a = 9.4
ELEN [110]
Well you can start by drawing a triangle with the information 

the size of angle B can be found using the Law of Sine

\frac{sin(150)}{9.4)}  =  \frac{sin(B)}{4.8}

the size of angle C can be found using angle sum of a triangle. 

The length of side c can be found using the Law of Cosines

c^2 = 4.8^2 + 9.4^2 - 2 \times4.8\times9.4\times  cos(C)

hope it helps
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3 years ago
Compute the probability of flipping a coin once and getting heads, given that the previous flip was tails.
ra1l [238]

Answer:

the probability to flip a head is 50%

Step-by-step explanation:

I think.

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2 years ago
M
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Answer:

the answer is B

Step-by-step explanation:

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3 years ago
Maria y juan deben realizar el mapamundi en medio pliego de cartulina para la tarea de sociales pero cada uno tiene un cuarto de
kondor19780726 [428]

Answer:

Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:

  • <u>Verdadero</u>.

Step-by-step explanation:

Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:

  • Total de cartulina de María y Juan = \frac{1}{4}+\frac{1}{4}
  • Total de cartulina de María y Juan = \frac{4+4}{16}
  • Total de cartulina de María y Juan = \frac{8}{16}

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:

  • Total de cartulina de María y Juan = \frac{4}{8}
  • Total de cartulina de María y Juan = \frac{2}{4}
  • <u><em>Total de cartulina de María y Juan = </em></u>\frac{1}{2}<u><em /></u>

Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.

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I feel u

Step-by-step explanation:u need help too

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